Ok. No problem. I will answer anything u got
That's simplied already, unless they want a decimal then it's .6 or something
2x-2 must be zero or greater, since we cannot have a negative quantity under the radical sign (unless we allow for imaginary roots).
Solving 2x-2≥0, we get x-1≥0, or x≥1. x must be equal to or greater than 1.
16 - 16, so the answer to the 2nd problem is the fourth one: x=4.
Answer:
a) 0.012ft³
b)2.09 lb
c)0.791 lb
d) 0.012ft³
e) 6 inches
Step-by-step explanation:
a) To determine the volume of the shell of the jar we must determine the volume of the hollow cylinder:
Where r is the inside radius and R the outer radius.
convert to cubic ft:
The volume of the glass shell is 0.012 ft³
b) The weight of the cylinder can be determined because we have the volume and the density. Weight is defined as the product of volume and density:
The weight of the jar is 2.09 lb
c) The displacement of water is just the density of water mutliplied by the volume of the jar:#
0.791 lb of water will be displaced.
d) The volume of the water displaced is:
[tex]=0.791/62.5=0.01266
e) The jar will be fully submerged because the density of the jar is larger than water.
Answer:
u = (-21)/20
Step-by-step explanation:
Solve for u:
u + 1/4 = (-4)/5
Put each term in u + 1/4 over the common denominator 4: u + 1/4 = (4 u)/4 + 1/4:
(4 u)/4 + 1/4 = -4/5
(4 u)/4 + 1/4 = (4 u + 1)/4:
1/4 (4 u + 1) = -4/5
Multiply both sides of (4 u + 1)/4 = (-4)/5 by 4:
(4 (4 u + 1))/4 = (-4)/5×4
4×(-4)/5 = (4 (-4))/5:
(4 (4 u + 1))/4 = (-4×4)/5
(4 (4 u + 1))/4 = 4/4×(4 u + 1) = 4 u + 1:
4 u + 1 = (-4×4)/5
4 (-4) = -16:
4 u + 1 = (-16)/5
Subtract 1 from both sides:
4 u + (1 - 1) = (-16)/5 - 1
1 - 1 = 0:
4 u = (-16)/5 - 1
Put (-16)/5 - 1 over the common denominator 5. (-16)/5 - 1 = (-16)/5 - 5/5:
4 u = (-16)/5 - 5/5
-16/5 - 5/5 = (-16 - 5)/5:
4 u = (-16 - 5)/5
-16 - 5 = -21:
4 u = (-21)/5
Divide both sides by 4:
u = ((-21)/4)/5
5×4 = 20:
Answer: u = (-21)/20
