The time taken for radio signal to the earth's surface we shall proceed as follows;
time=(distance)/(speed)
Distance=7.5×10^6 meters
speed=3×10^8 meters/second
therefore:
Time=(7.5×10^6)/(3×10^8)=0.025 seconds
We conclude that it will take the signal 0.025 seconds to reach the surface of the earth.
A "system" of equations is a set or collection of equations that you deal with all together at once. Linear equations (ones that graph as straight lines) are simpler than non-linear equations, and the simplest linear system is one with two equations and two variables.
Answer:
EBC = 90
FBG = 25
ABF = 115
ABG = 140
EBG = 50
<u>H</u><u>o</u><u>p</u><u>e</u><u> </u><u>t</u><u>h</u><u>a</u><u>t</u><u> </u><u>h</u><u>e</u><u>l</u><u>p</u><u>e</u><u>d</u><u> </u><u>:</u><u>)</u>
Answer:
the question is not precise... sold each dozen or each egg?
clarify
<span>If there has to be 2 men and 2 women, we know
that we must take a group of 2 men out of the group of 15 men and a group of 2
women out of the group of 20 women. Therefore, we have:
(15 choose 2) x (20 choose 2)
(15 choose 2) = 105
(20 choose 2) = 190
190*105 = 19950
Therefore, there are 19950 ways to have a group of 4 with 2 men and 2women.</span>
<span>If there has to be 1 man and 3 women, we know
that we must take a group of 1 man out of the group of 15 men and a group of 3
women out of the group of 20 women. Therefore, we have:
(15 choose 1) x (20 choose 3)
(15 choose 1) = 15
(20 choose 3) = 1140
15*1140 = 17100
Therefore, there are 17100 ways to have a group of 4 with 3 women and 1 man.</span>
<span>We now find the total outcomes of having a group
with 4 women.
We know this is the same as saying (20 choose 4) = 4845</span>
Therefore, there are 4845 ways to have a group of
4 with 4 women.
We now add the outcomes of 2 women, 3 women, and
4 women and get the total ways that a committee can have at least 2 women.
19950 + 17100 + 4845 = 41895 ways that there will
be at least 2 women in the committee
