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DiKsa [7]
2 years ago
13

ILL MARK BRAINIEST IF YOU DO THIS CORRECTLY!!!

Mathematics
2 answers:
Anton [14]2 years ago
5 0

-2.2x3.4= -74.8

42/-6= -7/10

-3 3/5-( 3 1/10)= -21/10

-2 3/4+(3 1/6)= -2

!I might be wrong!

Someone check this!

Thank you!

Bess [88]2 years ago
4 0

Answer:

I think thats the answer. Check it. (:

Step-by-step explanation:

You might be interested in
Which statements are true?
GaryK [48]
<h3>Answer:</h3><h3>There are 3 true statements, and the true statements are: </h3><h3>choice A, choice C, choice D</h3>

======================================================

Explanation:

A. True. All triangles have 3 straight sides and 3 angles.

B. False. All triangles are polygons. A polygon is just a collection of line segments glued together to form a closed shape.

C. True. A plane figure is a flat shape.

D. True. See choice A.

E. False. Some triangles do not have one right angle. Example: obtuse triangles do not have any right angles.

7 0
3 years ago
How many positive integers between 1000 and 9999 inclusive
bekas [8.4K]

Answer:

Step-by-step explanation:

a.

first number is  1000-1+9=1008

9)1000(1

    9

-------

     10

       9

    -----

       10

         9

       ----

         1

       ----

last number is 9999

9| 9999

  ---------

    1111 |0

    --------

9999=1008+(n-1)9

9999-1008=(n-1)9

n-1=8991/9=999

n=999+1=1000

b.

first digit=1000

last digit=9999-1=9998

2 |9999

  ---------

  |4999|1

9998=1000+(n-1)2

(n-1)2=9998-1000=8998

n-1=4499

n=4499=1=5000

c.not sure

d.

total  numbers=9000

9999=1000+(n-1)1

9999-1000=n-1

n=8999+1=9000

numbers divisible by 3=3000

first number=1002

last number=9999

9999=1002+(n-1)3

(n-1)3=9999-1002=8997

n-1=2999

n=2999+1=3000

numbers not divisible by 3=9000-3000=6000

e.

numbers divisible by 5=1800

first number=1000

last number=9995

9995=1000+(n-1)5

(n-1)5=9995-1000=8995

n-1=1799

n=1799+1=1800

numbers divisible by 7=1286

7 | 1000

  ---------

  |  142-6

1000-6+7=1001

7 | 9999

  |---------

    1428-3

9999-3=9996

first digit=1001

last digit=9996

9996=1001+(n-1)7

(n-1)7=9996-1001=8995

n-1=1285

n=1285+1=1286

numbers divisible by 35=257

first digit=1015

35 ) 1000 ( 28

        70

       ----

        300

        280

        ------

           20

           ---

1000-20+35=1015

35)9999(285

     70

    ----

     299

     280

     -----

        199

        175

        ----

          24

         ----

last digit=9999-24=9975

9975=1015+(n-1)35

(n-1)35=9975-1015=8960

n-1=8960/35=256

n=257

reqd. numbers=1800+1286-257=3019

7 0
3 years ago
The Vilas County News earns a profit of $20 per year for each of its 3,000 subscribers. Management projects that the profit per
Mekhanik [1.2K]

Answer:

850

Step-by-step explanation:

Current profit per year = $ 20

Number of subscribers = 3000

For each additional subscriber over 3000, the profit will increase by 1 cent or by $ 0.01. For example, for 3001 (3000 + 1) subscribers, the profit will be $ 20.01 per year. Similarly, for 3002 (3000 + 2) subscribers, the profit will be $20.02 per year and so on.

So, for x additional subscribers over 3000, the profit will increase by 0.01(x). i.e. for (3000 + x) subscribers, the profit will be $(20 + 0.01x)

Since, profit per each subscriber is $(20 + 0.01x), the profit for (3000 + x) subscribers will be:

Total profit = Number of subscribers x Profit per each subscriber

Total profit = (3000 + x)(20 + 0.01x)

We want to calculate how many subscribers will be needed to bring a profit of $109,725. So, we replace Total profit by $109,725. The equation now becomes:

109725=(3000+x)(20+0.01x)\\\\ 109725=60000+30x+20x+0.01x^{2}\\\\ 0.01x^{2}+50x+60000-109725=0\\\\ 0.01x^{2}+50x-49725=0\\

Using quadratic formula, we can solve this equation as:

\\ x=\frac{-50 \pm \sqrt{50^{2}-4(0.01)(-49725)}}{2(0.01)}\\\\ x=\frac{-50 \pm67}{0.02}\\\\ x=\frac{-50-67}{0.02} , x=\frac{-50+67}{0.02}\\\\  x=-5850, x=850

x = -5850 is not a possible solution as this would make the total number of subscribers to be negative. So we reject this value.

Therefore, the answer to this question is 850. 850 more subscribers are needed to being a total profit of $109,725

8 0
3 years ago
The height of a free falling object at time t can be found using the function, h(t) = - 12t2 + 36t. Where h(t) is the height in
never [62]
For this case we have the following equation:
 h (t) = - 12t2 + 36t
 When the object hits the ground we have:
 - 12t2 + 36t = 0
 We look for the roots of the polynomial:
 t1 = 0
 t2 = 3
 Therefore, the time it takes the object to hit the ground is:
 t = 3 s
 Answer:
 
the time when the object hits the ground is:
 
t = 3 s
7 0
3 years ago
Read 2 more answers
Help math problem please anyone
kondor19780726 [428]
1/15 is how much further it is

8 0
3 years ago
Read 2 more answers
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