Answer:
P= 7/9 miles
A= (7/18) miles²
Step-by-step explanation:
Length 'l' = (1/6) mile
Width 'w'= (2/9) mile
Perimeter 'P' is given by:
'P' = 2l + 2w => 2(1/6) + 2(2/9)
P= 7/9 miles
Area 'A' is given by:
A= l x w =(1/6) x (2/9) = (7/18) miles²
Length and width of rectangle is 15 inches and 6 inches respectively
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Solution:</u></h3>
Given that area of a rectangle is 90 square inch
Ratio of length to the width = 5: 2.
Need to determine length and width of rectangle.
As ratio of length to the width is 5 : 2
Lets assume length of rectangle = 5x inches and width of rectangle = 2x inches.
<em><u>The formula for area of rectangle is given as:</u></em>

Substituting the given value of area of rectangle and assumed value of length and width of rectangle we get:

On solving the above expression for x we get


Hence length and width of rectangle is 15 inches and 6 inches.
Answer:
7x+5y=700
91 student tickets
Step-by-step explanation:
7x+5y=700
7(35)+5y=700
245+5y=700
5y=455
y=91
Hi,
x + y = 350 (equation 1)
3x + 2y = 950 (equation 2)
Use Substitution Method
Isolate variable x in equation 1
x = 350 – y (equation 3)
Substitute equation 3 into equation 2
3(350 – y) + 2y = 950
1050 – 3y + 2y = 950
3y – 2y = 1050 – 950
y = 100
Substitute y = 100 into equation 1
x + 100 = 350
x = 250
Answer: 250 $3 tickets and 100 $2 tickets were sold.