Question

The point (-2,2) is one endpoint of a segment that has a length of 10.049 units. The other endpoint is in quadrant 3 and has an x-coordinate od -3. What is the y-coordinate of the endpoint in quadrant 3

Answer 1

Answer:

The y coordinate is -7.999 ≈ -8

Step-by-step explanation:

One of the points on line segment is given as (-2,2).

The distance given is 10.049 units.

The x coordinate of other point is given as -3. Thus the point is (-3 , y),

where y is y coordinate of point lying in third quadrant.

The distance formula is given as,

Distance = $\sqrt{(x1-x2)^{2} + (y1-y2)^{2}}$, where

(x1,y1) and (x2,y2) are endpoints of line segment.

Inserting above two points and equating to 10.049 units,

$10.049 = \sqrt{((-2)-(-3))^{2} + ((2)-y)^{2}}$

Squaring both the sides,

$100.982 = (1)^{2} + ((2)-y)^{2}$

$99.982 = ((2)-y)^{2}$

+9.999 = (2-y) or -9.999 = (2-y)

y = 2-9.999     or y = 2+9.999

y = - 7.999 0r 11.999

But, point lies in third quadrant and is negative.

thus, y = -7.999