If the total value of the coins is $15. The number of each type of coin is: 31 quarters, 72 dimes.
<h3>Number of each type of coin</h3>
Let D = number of dimes
Let Q = the number of quarters
Equations
d + q = 103
0.10d + 0.25q = 15
d = 103 -q
0.10(103 -q) + 0.25q = 15
10.3 - 0.10q + 0.25q = 15
0.15q = 4.7
q=4.7/0.15
q=31 quarters
Substitute q into second equation
D+31=103
D=72 dimes
Therefore the number of each type of coin is: 31 quarters, 72 dimes.
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Answer:
c=
Step-by-step explanation:
a=height=6
b=length=4
using pythagorean theorem
a^2+b^2=c^2
36+16=c^2
c=
c=
Answer:
A
Step-by-step explanation:
hope this helped! please let me know if im wrong
There's a key problem in this question compelling you to actually rewrite it like that! Mathematically that is inaccurate and incorrect. If you do 72(8+19) it seems as if you are going to do 8+19*72 as in algebra whatever is outside the bracket is bound to go multiplied so technically (8+19)+72 would make more sense and the answer is
Using bidmas do the brackets first
8+19= 27
27+72=99
There isnt enough information to solve the question, answer is E.