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marusya05 [52]
3 years ago
5

Help, please! find x

Mathematics
1 answer:
nikdorinn [45]3 years ago
6 0

This shape consists of two primary special triangles, 30-60-90 and 45-45-90.

the side with the 60° will be half of the hypotenuse because 30° is across from it.

the side with the 30° will be 5.5√3 because 60° is across from it, and any sides that has 60° across from it is associated with a √3.

x is 5.5√6 because any sides that is "below" the 45° angles are associated with a √2 times the side that's above the 45°

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Vernon tossed a coin 20 times. The results were 8 head s and 12 tails. What is the experimental probability of tossing heads?
solmaris [256]

Answer:

2/5

Step-by-step explanation:

The experimental probability is

P (heads) = number of heads/ total tosses

                = 8/20

                 = 2/5

8 0
3 years ago
The value, y, in dollars of an autographed basketball after x years can be represented by the function y=4000(1.05)x.
Contact [7]

Answer:

I took the test!!

Step-by-step explanation:

Pit this in your calculator exactly like this 4,000(1.05)^5 and you get the answer 5,105.12625. So round your answer to the nearest dollar, which is 5,105.

8 0
3 years ago
Graph this rational equation. Identify the points of discontinuity, holes, vertical asymptotes, x-intercepts, and horizontal asy
irakobra [83]

Step-by-step explanation:

We have given,

A rational function : f(x) = \frac{x-2}{x-4}

W need to find :

Point of discontinuity : - At x = 4, f(x) tends to reach infinity, So we get discontinuity point at x =4.

For no values of x, we get indetermined form (i.e \frac{0}{0}), Hence there is no holes

Vertical Asymptotes:

Plug y=f(x) = ∞ in f(x) to get vertical asymptote   {We can us writing ∞ = \frac{1}{0}}

i.e ∞ = \frac{x-2}{x-4}

or \frac{1}{0}=\frac{x-2}{x-4}

or x-4 =0

or x=4, Hence at x = 4, f(x) has a vertical asymptote

X -intercept :

Plug f(x)=0 , to get x intercept.

i.e 0 = \frac{x-2}{x-4}

or x - 2 =0

or x = 2

Hence at x=2, f(x) has an x intercept

Horizontal asymptote:

Plug x = ∞ in f(x) to get horizontal asymptote.

i.e f(x) = \frac{x-2}{x-4} = \frac{x(1-\frac{2}{x} )}{x(1-\frac{4}{x} )}

or f(x) = \frac{(1-\frac{2}{∞} )}{(1-\frac{4}{∞} )}

or f(x) = 1 = y

hence at y =f(x) = 1, we get horizontal asymptote





4 0
3 years ago
I know this question is easy, but I don’t really know how to do it? Help? If possible put a quick explanation, it’s fine if not!
lorasvet [3.4K]

Answer:

She left $10.62 the total was $58.87

Hope this helps :)

3 0
3 years ago
5.35/46= ? i hate my mah class cane someone help me
KatRina [158]

Answer:

0.7

Step-by-step explanation:

Glad to help :)

7 0
3 years ago
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