Which table represents a nonlinear function?

What is the simplified form of each expression? 7x^–8 × 6x^3

klio [65]

7*6*x^-8*x^3
42x^-8+3 (bases same powers add)
42x^-5
1/42x^5
so the simplified form of 7x^-8*6x^3 is=1/42x^5

7 0

3 years ago

Please help no idea how to start it The radius is 2.5 m

Talja [164]

$2.5 \div 2 = 1.25$
so 1.25 is the right answer not sure tho

6 0

3 years ago

What is the average bowling score

Sveta_85 [38]

Answer:

77 is the average bowling score

6 0

3 years ago

Read 2 more answers

How i can answer this question, NO LINKS, if you answer correctly i will give u brainliest!

Firlakuza [10]

Answer: C) Today's soup will taste the same

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Explanation:

The usual recipe has 9 tomatoes for every 12 bowls. This forms the ratio 9:12.

Divide both parts of the ratio by 12 to end up with 0.75:1

9/12 = 0.75
12/12 = 1

The ratio 0.75:1 means that there are 0.75 tomatoes for each bowl.

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Then the restaurant updates the recipe to involve 6 tomatoes for every 8 bowls, leading to the ratio 6:8. Divide both parts by 8

6/8 = 0.75
8/8 = 1

The ratio 6:8 is the same as 0.75:1

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We get the same ratio (0.75:1) each time we turn that second number into a 1, which means that each bowl involves the same number of tomatoes. Therefore, the taste should be the same.

Of course the concept of taste is subjective, meaning that the taste could easily vary over time even if you involved the same number of tomatoes. Also, the taste may vary from person to person. However, there should be an objective way to measure the "tomato"ness of each bowl.

4 0

2 years ago

g 78% of all Millennials drink Starbucks coffee at least once a week. Suppose a random sample of 50 Millennials will be selected

Tatiana [17]

Answer:

We know that n = 50 and p =0.78.

We need to check the conditions in order to use the normal approximation.

$np=50*0.78=39 \geq 10$

$n(1-p)=50*(1-0.78)=11 \geq 10$

Since both conditions are satisfied we can use the normal approximation and the distribution for the proportion is given by:

$p \sim N (p, \sqrt{\frac{p(1-p)}{n}})$

With the following parameters:

$\mu_ p = 0.78$

$\sigma_p = \sqrt{\frac{0.78*(1-0.78)}{50}}= 0.0586$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

We know that n = 50 and p =0.78.

We need to check the conditions in order to use the normal approximation.

$np=50*0.78=39 \geq 10$

$n(1-p)=50*(1-0.78)=11 \geq 10$

Since both conditions are satisfied we can use the normal approximation and the distribution for the proportion is given by:

$p \sim N (p, \sqrt{\frac{p(1-p)}{n}})$

With the following parameters:

$\mu_ p = 0.78$

$\sigma_p = \sqrt{\frac{0.78*(1-0.78)}{50}}= 0.0586$

6 0

3 years ago