Answer:
Car B by 20km/hr
Step-by-step explanation:
well, we first calculate the speeds of both cars. there is an allocated dot along the 6 hour mark for the line graph of both cars. hence, using a time of 6 hours, we use their respective distances to produce an answer. car a has travelled 360 km while car v has travelled 480 km.
hence:
speed of car b = 480/6 = 80
speed of car a = 360/6 = 60
Answer. The standard form of a line is in the form Ax + By = C where A is a positive integer, and B, and C are integers. Hope this helps, let me know if it’s correct so others can use it :)
Good luck.
-x -13 = 35
- x = 48
x = -48
Answer:
The probability the event that none of them are obese is 0.0352.
Step-by-step explanation:
<h3>Binomial distribution:</h3>
A discrete random variable X having to the set {0,1,2,3....,n} as the spectrum, is said to have binomial distribution with parameters n= the number of trial, and p= probability of successes on an individual trial , if the p.m.f of X is given by,
for x=0,1,2,...,n
=0 elsewhere.
where 0<p<1 and n an positive integer,
Given that,
The probability of the event that a child living in an urban area in the united state is obese is 20%.
n=Number of children = 15, p= 20%= 0.20.
The probability the event that none of them are obese is
=P(X=0)
![=\left(\begin{array}{c}15\\0\end{array}\right) (0.20)^0(1-0.20)^{15-0}](https://tex.z-dn.net/?f=%3D%5Cleft%28%5Cbegin%7Barray%7D%7Bc%7D15%5C%5C0%5Cend%7Barray%7D%5Cright%29%20%280.20%29%5E0%281-0.20%29%5E%7B15-0%7D)
=0.0352
Answer:
![\sf (x+2)^2+(y-2)^2=2](https://tex.z-dn.net/?f=%5Csf%20%28x%2B2%29%5E2%2B%28y-2%29%5E2%3D2)
Step-by-step explanation:
If RS is the diameter of the circle, then the midpoint of RS will be the center of the circle.
![\sf midpoint=\left(\dfrac{x_s-x_r}{2}+x_r,\dfrac{y_s-y_r}{2}+y_r \right)](https://tex.z-dn.net/?f=%5Csf%20midpoint%3D%5Cleft%28%5Cdfrac%7Bx_s-x_r%7D%7B2%7D%2Bx_r%2C%5Cdfrac%7By_s-y_r%7D%7B2%7D%2By_r%20%5Cright%29)
![\sf =\left(\dfrac{-1-(-3)}{2}+(-3),\dfrac{3-1}{2}+1 \right)](https://tex.z-dn.net/?f=%5Csf%20%3D%5Cleft%28%5Cdfrac%7B-1-%28-3%29%7D%7B2%7D%2B%28-3%29%2C%5Cdfrac%7B3-1%7D%7B2%7D%2B1%20%5Cright%29)
![\sf =(-2, 2)](https://tex.z-dn.net/?f=%5Csf%20%3D%28-2%2C%202%29)
Equation of a circle: ![\sf (x-h)^2+(y-k)^2=r^2](https://tex.z-dn.net/?f=%5Csf%20%28x-h%29%5E2%2B%28y-k%29%5E2%3Dr%5E2)
(where (h, k) is the center and r is the radius)
Substituting found center (-2, 2) into the equation of a circle:
![\sf \implies (x-(-2))^2+(y-2)^2=r^2](https://tex.z-dn.net/?f=%5Csf%20%5Cimplies%20%28x-%28-2%29%29%5E2%2B%28y-2%29%5E2%3Dr%5E2)
![\sf \implies (x+2)^2+(y-2)^2=r^2](https://tex.z-dn.net/?f=%5Csf%20%5Cimplies%20%28x%2B2%29%5E2%2B%28y-2%29%5E2%3Dr%5E2)
To find
, simply substitute one of the points into the equation and solve:
![\sf \implies (-3+2)^2+(1-2)^2=r^2](https://tex.z-dn.net/?f=%5Csf%20%5Cimplies%20%28-3%2B2%29%5E2%2B%281-2%29%5E2%3Dr%5E2)
![\sf \implies 1+1=r^2](https://tex.z-dn.net/?f=%5Csf%20%5Cimplies%201%2B1%3Dr%5E2)
![\sf \implies r^2=2](https://tex.z-dn.net/?f=%5Csf%20%5Cimplies%20r%5E2%3D2)
Therefore, the equation of the circle is:
![\sf (x+2)^2+(y-2)^2=2](https://tex.z-dn.net/?f=%5Csf%20%28x%2B2%29%5E2%2B%28y-2%29%5E2%3D2)