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3 years ago

How many leaves on a tree diagram are needed to represent all possible combinations tossing a coin 3 times?

2 answers:

8 0

N = 3 is the number of times the coin is tossed. Since there are 2 outcomes per toss, this means that there are 2^n = 2^3 = 2*2*2 = 8 outcomes total. Therefore, there are 8 leaves total.

If we make
H = heads
T = tails

Then here are the 8 outcomes in the sample space
HHH
HHT
HTH
THH
HTT
THT
TTH
TTT

vladimir1956 [14]3 years ago

4 0

There are 8 combinations. A P E X :)

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A farmer had 1,000 horses and cows. After selling some of them, he had 550 horses and 350 cows left. How many horses and cows di

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The farmer had sold 100 horses and cows

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Answer:

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Step-by-step explanation:

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3 years ago

What is the mode of this set of data? 1982 1988 1989 1994 1995 2005

Cerrena [4.2K]

All of the numbers are the mode, so it is
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3 years ago

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Fatima’s softball practice starts at 9:30 a.m. Practice lasts for 1 hour and 10 minutes.

ki77a [65]

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2 years ago

Read 2 more answers

The expected number of typographical errors on a page of a certain magazine is .2. What is the probability that an article of 10

Pavel [41]

Answer:

a) The probability that an article of 10 pages contains 0 typographical errors is 0.8187.

b) The probability that an article of 10 pages contains 2 or more typographical errors is 0.0175.

Step-by-step explanation:

Given : The expected number of typographical errors on a page of a certain magazine is 0.2.

To find : What is the probability that an article of 10 pages contains

(a) 0 and (b) 2 or more typographical errors?

Solution :

Applying Poisson distribution,

$N\sim Pois(0.2)$

$P(N=r)=\frac{e^{-np}(np)^r}{r!}$

where, n is the number of words in a page

and p is the probability of every word with typographical errors.

Here, n=10 and E(N)=np=0.2

a) The probability that an article of 10 pages contains 0 typographical errors.

Substitute r=0 in formula,

$P(N=0)=\frac{e^{-0.2}(0.2)^0}{0!}$

$P(N=0)=\frac{e^{-0.2}}{1}$

$P(N=0)=e^{-0.2}$

$P(N=0)=0.8187$

The probability that an article of 10 pages contains 0 typographical errors is 0.8187.

b) The probability that an article of 10 pages contains 2 or more typographical errors.

Substitute $r\geq 2$ in formula,

$P(N\geq 2)=1-P(N$

$P(N\geq 2)=1-[P(N=0)+P(N=1)]$

$P(N\geq 2)=1-[\frac{e^{-0.2}(0.2)^0}{0!}+\frac{e^{-0.2}(0.2)^1}{1!}]$

$P(N\geq 2)=1-[e^{-0.2}+e^{-0.2}(0.2)]$

$P(N\geq 2)=1-[0.8187+0.1637]$

$P(N\geq 2)=1-0.9825$

$P(N\geq 2)=0.0175$

The probability that an article of 10 pages contains 2 or more typographical errors is 0.0175.

6 0

3 years ago