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statuscvo [17]
3 years ago
5

A. 4 b. 5 c. 9 d. 25

Mathematics
1 answer:
trapecia [35]3 years ago
7 0
5t=45
45/5=9

The answer is C
Hope I helped
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Step-by-step explanation:

The solution is given as

y(x)=\frac{1}{\sqrt{C+4x^2}}

Now for the initial condition the value of C is calculated as

y(x)=\frac{1}{\sqrt{C+4x^2}}\\y(-2)=\frac{1}{\sqrt{C+4(-2)^2}}\\4=\frac{1}{\sqrt{C+4(4)}}\\4=\frac{1}{\sqrt{C+16}}\\16=\frac{1}{C+16}\\C+16=\frac{1}{16}\\C=\frac{1}{16}-16

So the solution is given as

y(x)=\frac{1}{\sqrt{C+4x^2}}\\y(x)=\frac{1}{\sqrt{\frac{1}{16}-16+4x^2}}

Simplifying the equation as

y(x)=\frac{1}{\sqrt{\frac{1}{16}-16+4x^2}}\\y(x)=\frac{1}{\sqrt{\frac{1-256+64x^2}{16}}}\\y(x)=\frac{\sqrt{16}}{\sqrt{{1-256+64x^2}}}\\y(x)=\frac{4}{\sqrt{{1+64(x^2-4)}}}

So the correct option is 4

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