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Alja [10]
3 years ago
11

Differentiate y= ln (6 – 3x)^4​

Mathematics
1 answer:
dsp733 years ago
3 0

Step-by-step explanation:

\frac{dy}{dx}  =  \frac{1}{ {(6 - 3x)}^{4} }  \times  {4(6 - 3x)}^{3} ( - 3) \\  =   \frac{ - 12 {(6 - 3x)}^{3} }{ {(6 - 3x)}^{4} }   \\  =  -  \frac{12}{6 - 3x}

I hope I'm correct. I've never learnt differentiation for log and exponents before

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