2 years ago

Differentiate y= ln (6 – 3x)^4

1 answer:

dsp732 years ago

3 0

Step-by-step explanation:

$\frac{dy}{dx} = \frac{1}{ {(6 - 3x)}^{4} } \times {4(6 - 3x)}^{3} ( - 3) \\ = \frac{ - 12 {(6 - 3x)}^{3} }{ {(6 - 3x)}^{4} } \\ = - \frac{12}{6 - 3x}$

I hope I'm correct. I've never learnt differentiation for log and exponents before

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