Question

Differentiate y= ln (6 – 3x)^4​

Answer 1

Step-by-step explanation:

$\frac{dy}{dx} = \frac{1}{ {(6 - 3x)}^{4} } \times {4(6 - 3x)}^{3} ( - 3) \\ = \frac{ - 12 {(6 - 3x)}^{3} }{ {(6 - 3x)}^{4} } \\ = - \frac{12}{6 - 3x}$

I hope I'm correct. I've never learnt differentiation for log and exponents before