Question

Lois rode her bike to visit a friend. She traveled at 10 mi/h. While she was there, it began to rain. Her friend drove her home in a car traveling at 25 mi/h. Lois took 1.5 h longer to go to her friend’s than to return home. How many hours did it take Lois to ride to her friend’s house?

Answer 1

Answer:

distance(d)=rate(r) times time(t) or d=rt; r=d/t and t=d/r

Let t=time it took Lois to ride home in the car

Then (t+1.5)=time it took Lois to bike to her friends

(1) distance she travelled on a bike=rt=10*(t+1.5)

(2) distance she travelled back in the car=25*t

Now we know that (1)distance going=(2)distance coming back in the car. So:

10(t+1.5)=25t get rid of parens

10t+15=25t subtract 10t from both sides

10t-10t+15=25t-10t collect like terms

15=15t divide both sides by 15

t=1 hour time it took to ride home in the car

t+1.5=1+1.5=2.5 hrs-------------------------time it took biking to her friends

CK

2.5*10=1*25

25=25

Step-by-step explanation: