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2 years ago

What is the value of x + y(3 − x) when x = −5 and y = 3?

Mathematics

2 answers:

grandymaker [24]2 years ago

6 0

Answer:

Step-by-step explanation:

x + y(3 − x)

Let x = -5 and y = 3

-5 +3(3 - -5)

Subtracting a negative is like adding

-5 +3(3+5)

Parentheses first

-5 +3(8)

Multiply

-5+24

Subtract

sleet_krkn [62]2 years ago

5 0

Answer:

19

Step-by-step explanation:

x + y(3 - x) x = -5 y = 3

Step 1. Substitute x for -5 and y for 3

(-5) + (3)(3 - (-5))

Step 2. Solve for (3 - (-5))

(-5) + (3)(8)

Step 3. Multiply 3 and 8

(-5) + 24

Step 4. Add -5 and 24

(-5) + 24 = 24 + -5 = 19

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The inverse of the function f(x) = 4(x-3)² + 2 is $f^{-1}(x) = \sqrt{\frac{x-2}{4} } + 3$

The given function is:

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To find the inverse of the function:

Make x as the subject of the formula

$4(x-3)^2 = f(x) - 2\\(x-3)^2 = \frac{f(x)-2}{4} \\x - 3 = \sqrt{\frac{f(x)-2}{4} } \\x = \sqrt{\frac{f(x)-2}{4} } + 3$

Replace x by $f^{-1}(x)$ and replace f(x) by x

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Therefore, the inverse of the function is:

$f^{-1}(x) = \sqrt{\frac{x-2}{4} } + 3$

Learn more here: brainly.com/question/17285960

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