I'd suggest using "elimination by addition and subtraction" here, altho' there are other approaches (such as matrices, substitution, etc.).
Note that if you add the 3rd equation to the second, the x terms cancel out, and you are left with the system
- y + 3z = -2
y + z = -2
-----------------
4z = -4, so z = -1.
Next, multiply the 3rd equation by 2: You'll get -2x + 2y + 2z = -2.
Add this result to the first equation. The 2x terms will cancel, leaving you with the system
2y + 2z = -2
y + z = 4
This would be a good time to subst. -1 for z. We then get:
-2y - 2 = -2. Then y must be 0. y = 0.
Now subst. -1 for z and 0 for y in any of the original equations.
For example, x - (-1) + 3(0) = -2, so x + 1 = -2, or x = -3.
Then a tentative solution is (-3, -1, 0).
It's very important that you ensure that this satisfies all 3 of the originale quations.
Answer: 18
Step-by-step explanation:
Answer:
m = -6/5
Step-by-step explanation:
The points present are (-2,2) and (3,-4).
m = -4 - 2 / 3 - (-2)
m = -4 - 2 / 3 + 2
m = -6/5
Answer:
5/9
Step-by-step explanation:
Let the denominator be x and numerator be y.
Given, numerator is 4 less than denominator
=> y = x - 4 ...(1)
When 5 is added to both:
Numerator = y + 5 , and, denominator = x + 5
Now their ratio is 5/7.
=> (y + 5)/(x + 5) = 5/7
=> 7(y + 5) = 5(x + 5)
=> 7y + 35 = 5x + 25
=> 7y - 5x = 25 - 35
=> 7(x - 4) - 5x = -10 {y=x-4}
=> 7x - 28 - 5x = -10
=> 2x = 18
=> x = 9
Thus,
Fraction is y/x = (x-4)/x = (9-4)/9 = 5/9
Answer:
answer will be 0
plz mark me as brainliest
