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3 years ago

5

In the figure PQ || RS, find the value of x.

1 answer:

ki77a [65]3 years ago

8 0

The value of x in the figure is 125°

And the right option is (D) 125°

To solve the problem, we use the formular for the sum of the interior angle of a polygon.

(n-2)180°

When a vertical line is drawn to touch point Q and S, it becomes a pentagon.

Pentagon: A pentagon is a polygon with 5 sides

The sum of the angle in a pentagon is

$(5-2)180 = 540$

From the figure,

∠P+∠T+∠R+∠Q+∠S = 540°

$35+200+x+90+90 = 540$

$415+x = 540$

$x = 540-415$

$x = 125$

Hence the value of x in the figure is 125°

And the right option is (D) 125°

Learn more about polygons here: brainly.com/question/17042929

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3 years ago

Which graph represents the function f(x)= 0.2^x + 3

Dennis_Churaev [7]

The third graph or bottom left graph represents $f(x) = 0.2^{x} + 3.$

Step-by-step explanation:

Step 1:

To determine which of the given graphs represents the equation $f(x) = 0.2^{x} + 3$ , we substitute some values in the place of x.

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Step 2:

Now we substitute another value to determine which graph represents $f(x) = 0.2^{x} + 3.$

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So the third graph or bottom left graph represents $f(x) = 0.2^{x} + 3.$

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What is the period of f(x) = sin(x)?

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Which of the following points are more than 5 units from the point P(−2, −2)? Select all that apply. A A (2, 1) B B (4, −1) C C

netineya [11]

The distance between any 2 points P(a,b) and Q(c,d) in the coordinate plane, is given by the formula:<span>

<span> $|PQ|= \sqrt{ (a-c)^{2} + (b-d)^{2}}$ </span></span>

Using this formula we calculate the distances |PA|, |PB|, |PC|, |PD| and |PE| and compare to 5.

$|PA|= \sqrt{ (-2-2)^{2} + (-2-1)^{2}}= \sqrt{16+9}= \sqrt{25}=5$

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$|PC|= \sqrt{ (-2-2)^{2} + (-2+3)^{2}}= \sqrt{16+1}= \sqrt{17}\approx4$

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Answer: B and D

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3 years ago