Ratio of volume is a cubed: b cubed
Answer:
Step-by-step explanation:
To find the matrix A, took all the numeric coefficient of the variables, the first column is for x, the second column for y, the third column for z and the last column for w:
![A=\left[\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%261%262%262%5C%5C-7%26-3%265%26-8%5C%5C4%261%261%261%5C%5C3%267%26-1%261%5Cend%7Barray%7D%5Cright%5D)
And the vector B is formed with the solution of each equation of the system:![b=\left[\begin{array}{c}3\\-3\\6\\1\end{array}\right]](https://tex.z-dn.net/?f=b%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D3%5C%5C-3%5C%5C6%5C%5C1%5Cend%7Barray%7D%5Cright%5D)
To apply the Cramer's rule, take the matrix A and replace the column assigned to the variable that you need to solve with the vector b, in this case, that would be the second column. This new matrix is going to be called 
.
![A_{2}=\left[\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right]](https://tex.z-dn.net/?f=A_%7B2%7D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%263%262%262%5C%5C-7%26-3%265%26-8%5C%5C4%266%261%261%5C%5C3%261%26-1%261%5Cend%7Barray%7D%5Cright%5D)
The value of y using Cramer's rule is:
Find the value of the determinant of each matrix, and divide:
Answer: an arithmetic sequence
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
5a^2 - 44 = 81 Add 44 to both sides
5a^2 = 81 + 44 Collect like terms
5a^2 = 125 Divide both sides by 5
a^2 = 125/5
a^2 = 25 Take the square root of both sides
√a^2 = √25
a = +5
a = -5
The answer is B
5000
- Addition (+) and subtraction (-) round by the least number of decimals.
- Multiplication (* or ×) and division (/ or ÷) round by the least number of significant figures.
- Logarithm (log, ln) uses the input's number of significant figures as the result's number of decimals.
- Antilogarithm (n^x.y) uses the power's number of decimals (mantissa) as the result's number of significant figures.
- Exponentiation (n^x) only rounds by the significant figures in the base.
- To count trailing zeros, add a decimal point at the end (e.g. 1000.) or use scientific notation (e.g. 1.000 × 10^3 or 1.000e3).
- Zeros have all their digits counted as significant (e.g. 0 = 1, 0.00 = 3).
- Rounds when required, after parentheses, and on the final step.
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