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dolphi86 [110]
3 years ago
9

The length of a rectangle is 8cm less than twice it's width find the the dimensions of the rectangle if the area is 120cm(2)

Mathematics
1 answer:
Anton [14]3 years ago
5 0

Answer:

15 cm

Step-by-step explanation:

so:

if A= b x h and web have b Just Do the inverse formula:

H = a/b h=120/8 = 15 cm

Sorry for my bad English but I'm italian

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Weights of different sandwiches in two lengths are shown in the table.
Alexandra [31]

Answer:

Egg salad sandwich is proportional to its length

Step-by-step explanation:

Weight of Sandwiches by Length of Roll

                                        6-inch Roll      12-Inch Roll

Cheese sandwich               \frac{1}{4}                      \frac{3}{4}

Chicken salad sandwich     \frac{3}{4}                     1\frac{3}{4}

Egg salad sandwich            \frac{2}{3}                   1\frac{1}{3}

For cheese sandwich proportion

\frac{6}{\frac{1}{4}}=\frac{12}{\frac{3}{4}}\\24 \neq 16

So, Cheese sandwich weight is not proportional to its length

For Chicken salad sandwich proportion

\frac{6}{\frac{3}{4}}=\frac{12}{\frac{7}{4}}\\8 \neq \frac{48}{7}

So, chicken salad sandwich is not proportional to its length

For Egg salad sandwich  proportion

\frac{6}{\frac{2}{3}}=\frac{12}{\frac{4}{3}}\\9=9

So, egg salad sandwich is proportional to its length

6 0
2 years ago
Use the drop-down menus to choose steps in order to correctly solve 1+2b−13=12−4b−2b for b. Pls help
MrMuchimi

b=3

I found this out by subtracting and adding on both sides.

8 0
2 years ago
Read 2 more answers
WHAT IS THE REMAINDER WHEN <img src="https://tex.z-dn.net/?f=32%5E%7B37%5E%7B32%7D%20%7D" id="TexFormula1" title="32^{37^{32} }"
Feliz [49]

Recall Euler's theorem: if \gcd(a,n) = 1, then

a^{\phi(n)} \equiv 1 \pmod n

where \phi is Euler's totient function.

We have \gcd(9,32) = 1 - in fact, \gcd(9,32^k)=1 for any k\in\Bbb N since 9=3^2 and 32=2^5 share no common divisors - as well as \phi(9) = 6.

Now,

37^{32} = (1 + 36)^{32} \\\\ ~~~~~~~~ = 1 + 36c_1 + 36^2c_2 + 36^3c_3+\cdots+36^{32}c_{32} \\\\ ~~~~~~~~ = 1 + 6 \left(6c_1 + 6^3c_2 + 6^5c_3 + \cdots + 6^{63}c_{32}\right) \\\\ \implies 32^{37^{32}} = 32^{1 + 6(\cdots)} =  32\cdot\left(32^{(\cdots)}\right)^6

where the c_i are positive integer coefficients from the binomial expansion. By Euler's theorem,

\left(32^{(\cdots)\right)^6 \equiv 1 \pmod9

so that

32^{37^{32}} \equiv 32\cdot1 \equiv \boxed{5} \pmod9

7 0
1 year ago
Please help me with c this is confusing also is b correct?
OlgaM077 [116]

Answer: See attached.

Step-by-step explanation:

6 0
2 years ago
Consider the following system of equations. StartLayout Enlarged left-brace 1st row negative 10 x squared minus 10 y squared = n
ziro4ka [17]

These 2 equations has no solution and the equations are independent of each other.

<u>Step-by-step explanation:</u>

-10x² -10y² = -300 ----a

5x² + 5y² = 150 ---- b

While trying to solve this,

We can multiply the eq. b by 2 so we will get eq. c and then add to eq. a we will get 0 as the solution.

10x² + 10y² = 300 ----c

-10x² -10y² = -300 ---a

Everything cutoff, we will get 0, and there is no solution to these equations.

4 0
3 years ago
Read 2 more answers
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