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stealth61 [152]
3 years ago
11

In the book Business Research Methods, Donald R. Cooper and C. William Emory (1995) discuss a manager who wishes to compare the

effectiveness of two methods for training new salespeople. The authors describe the situation as follows: The company selects 22 sales trainees who are randomly divided into two equal experimental groups—one receives type A and the other type B training. The salespeople are then assigned and managed without regard to the training they have received. At the year’s end, the manager reviews the performances of salespeople in these groups and finds the following results: A Group B Group Average Weekly Sales x¯1 = $1,410 x¯2 = $1,049 Standard Deviation s1 = 203 s2 = 287 (a) Set up the null and alternative hypotheses needed to attempt to establish that type A training results in higher mean weekly sales than does type B training.
Mathematics
1 answer:
S_A_V [24]3 years ago
4 0

Answer:

Null hypothesis is: U1 - U2 ≤ 0

Alternative hypothesis is U1 - U2 > 0

Step-by-step explanation:

The question involves a comparison of the two types of training given to the salespeople. The requirement is to set up the hypothesis that type A training leads to higher mean weakly sales compared to type B training.

Let U1 = mean sales by type A trainees

Let U2 = mean sales by type B trainees

Therefore, the null hypothesis (H0) is: U1 - U2 ≤ 0

This implies that type A training does not result in higher mean weekly sales than type B training.

The alternative hypothesis (H1) is: U1 - U2 > 0

This implies that type A training indeed results in higher mean weekly sales than type B training.

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Greeley [361]

Answer:

Where is the triangle?

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Step-by-step explanation:

3 0
2 years ago
In a survey of students about favorite sports the results include 33 who like football, 13 who like tennis and football, 24 who
goblinko [34]

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How many students like only tennis and football?

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7 0
2 years ago
Given m LMN = 145°, what is m XMN?
astra-53 [7]

Answer:

m∠XMN = 80°

Step-by-step explanation:

you know that:

4x + 5 + 6x - 10 = 145

solve for x:

10x - 5 = 145

10x = 150

x = 15

Use this information to solve for m∠XMN

6(15) - 10

90 - 10

80

m∠XMN = 80°

7 0
2 years ago
Please help!<br> 5x^2 - 3x - 2 = 0<br> Solve using the zero-factor property.
Alex

Answer:

x = -2/5

x = 1

Step-by-step explanation:

5x² - 3x - 2 = 0

(5x + 2)(x - 1) = 0

⇒ 5x + 2 = 0

⇒ 5x = -2

⇒ x = -2/5

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7 0
2 years ago
A bakery was about to sell fresh baguettes, and people formed a line outside to wait. While waiting for the bread to bake, every
Vikentia [17]

Answer:

The number of people standing in the original line is 22 people

Step-by-step explanation:

The information given are;

The number of baguettes that was shared by the people on the line = 85

The number of baguettes each person received = 1 each

Therefore;

The number of people that were finally on the line = 85

Let the number of people in the original line = X

Then each space between two people in X was filled by 1 new person of the first set of people who joined the line

Therefore;

The number of the first set of people who joined the line = The number of spaces between two count of people in X

Which gives;

The number of people who joined the line = X - 1

The new total number of people on the line = X + X - 1 = 2·X - 1

As time passed, a second set of people joined the line such that each space between the people waiting was filled with a new person (from the second set) who joined the line

Therefore, the number of people in the second set = Number of people waiting - 1

Which gives;

The number of people in the second set = 2·X - 1 - 1 = 2·X - 2

The total number of people on the line becomes 2·X - 1 + 2·X - 2 = 4·X - 3

The 85 baguettes is then able to go round (each) among the total number of people on the line

Therefore;

The total number of people on the line = The number of baguettes sheared

4·X - 3 = 85

4·X = 85 + 3 = 88

X = 88/4 = 22

Therefore;

The number of people standing in the original line = 22.

8 0
3 years ago
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