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Colt1911 [192]
2 years ago
12

Let f(x) = 6x^2 + 5 and g(x) = 3x - 5. Find f(g(7)).

Mathematics
1 answer:
Vedmedyk [2.9K]2 years ago
8 0

Answer:

D) 1541

Step-by-step explanation:

I like to answer it w without deriving the formula of f(g(x)). So, we go this way, you firstly have to find g(7) which will be equal to 3 * 7 - 5 = 16.

And then you find f(16) = 6*16*16+5 = 1541. That's all.

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3 years ago
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If f(x) = 62.7"), what is 13)?
Lemur [1.5K]

Answer:

f(x)=|x−13|+11

To find the x

coordinate of the vertex, set the inside of the absolute value x−13 equal to 0. In this case, x−13=0

.

x−13=0

Add 13

to both sides of the equation.

x=13

Replace the variable x

with 13

in the expression.

y=|(13)−13|+11

Simplify |(13)−13|+11

.The absolute value vertex is (13,11)

hope this helps ;)

6 0
3 years ago
What is the expression for the area of this rectangle?
raketka [301]

Answer:

Step-by-step explanation:

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5 0
3 years ago
What is the horizontal asymptote of the function f(x)= -2x/x+1
daser333 [38]

<u>Answer:</u>

-2

<u>Step-by-step explanation:</u>

We have been given a function f(x)=\frac{-2x}{x+1} and we are asked to find the horizontal asymptote of our given function.

Recalling the rules for a horizontal asymptote:

1. If the numerator and denominator have equal degree, the horizontal asymptote will be the ratio of the leading coefficients.

2. If the polynomial of denominator has larger degree than the numerator, then the horizontal asymptote will be the x-axis or y=0.

3. If the polynomial of numerator has larger degree than denominator, then the function has no horizontal asymptote.

Here, the numerator and denominator are of the same degree. So the horizontal asymptote will be the ratio of the coefficients.

Horizontal asymptote = -\frac{2}{1} = -2

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Answer:

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Step-by-step explanation:

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