Answer:
Step-by-step explanation:
In this cross sections problem, we can integrate from -r to +r (so that the integral covers the entire base of the solid).
The formatting for the integral did not let me put -r on the lower bound, so i replaced it with a, just know that a represents -r here.
Evaluating the integral gives use that it is equal to;
Caution: this answer may not meet your needs, but this is the answer I have come up with with the given information.
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Answer:
Step-by-step explanation:
![\sf 3a^5-18a^3+6a^2\\\\HCF = 3a^2\\\\Take \ 3a^2 \ common\\\\= 3a^2(a^3-6a+2)\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Csf%203a%5E5-18a%5E3%2B6a%5E2%5C%5C%5C%5CHCF%20%3D%203a%5E2%5C%5C%5C%5CTake%20%5C%203a%5E2%20%5C%20common%5C%5C%5C%5C%3D%203a%5E2%28a%5E3-6a%2B2%29%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>
Answer:
h(2) = 7/4
h(-3) = -2
h(-2) = 11/(-8)
h(-3) - h(-2) = -(5/8)
Step-by-step explanation:
h(x) = (2x^2-x+1) / (3x-2)
h(2) = (2*2^2 - 2 + 1) / (3*2 - 2)
= (8 - 2 + 1) / (6 - 2)
= 7/4
h(-3) = {2*(-3)^2 - (-3) + 1} / {3*(-3) - 2}
= (18 + 3 + 1) / (-9 - 2)
= 22/(-11)
= -2
h(-2) = {2*(-2)^2 - (-2) + 1} / {3*(-2) - 2}
= (8 + 2 + 1) / (-6 - 2)
= 11/(-8)
h(-3) - h(-2) = (-2) - {11/(-8)}
= -(5/8)
Hope this will help. Please give me brainliest.
Answer:
x<3/8
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Step-by-step explanation:
Step 1: Simplify both sides of the inequality.
x+1/4<5/8
Step 2: Subtract 1/4 from both sides.
x + 1/4 - 1/4 < 5/8 - 1/4
x<3/8
