-1/6(2x + 12) = 1/3x + 12

A line parallel to $3x-7y = 65$ passes through the point $(7,4)$ and $(0,K)$. What is the value of K?

Zepler [3.9K]

Answer:

1

Step-by-step explanation:

Hi, its you again lol.

I am in elementary btw.

I don't want to put the equation down.

6 0

3 years ago

Maths -|-30-(10-20)|-|5-(10-15)|=? If someone helped me , I would be grateful

defon

Answer:

-30

Step-by-step explanation:

-|-30-(10-20)|-|5-(10-15)|=-|-30-(-10)|-|5-(-5)|

=-|-30+10|-|5+5|

=-|-20|-|10|

=-(20)-(10)

= -20-10

= -30

4 0

3 years ago

Is this a function? Why or why not? * 10 points Captionless Image

GrogVix [38]

Answer:

Wheres the function, what do u mean by captionless image

3 0

3 years ago

The bar graph in the following graphic represents fictional net exports in billions of dollars for five countries. Net exports a

harina [27]

Answer:

$80 billion

Step-by-step explanation:

From the graph, we have the following:

$United\ States = -110$

$Denmark = -30$

$China = 120$

$Germany = 40$

$Spain = 30$

Required

Determine the difference in US and Denmark exports

The difference is calculated as thus:

$Difference = Denmark - United\ States$

This gives:

$Difference = -30 - (-110)$

$Difference = -30 +110$

$Difference = 80$

Hence, the difference is $80 billion

8 0

2 years ago

An area is approximated to be 14 in 2 using a left-endpoint rectangle approximation method. A right- endpoint approximation of t

USPshnik [31]

The trapezoidal approximation will be the average of the left- and right-endpoint approximations.

Let's consider a simple example of estimating the value of a general definite integral,

$\displaystyle\int_a^bf(x)\,\mathrm dx$

Split up the interval $[a,b]$ into $n$ equal subintervals,

$[x_0,x_1]\cup[x_1,x_2]\cup\cdots\cup[x_{n-2},x_{n-1}]\cup[x_{n-1},x_n]$

where $a=x_0$ and $b=x_n$ . Each subinterval has measure (width) $\dfrac{a-b}n$ .

Now denote the left- and right-endpoint approximations by $L$ and $R$ , respectively. The left-endpoint approximation consists of rectangles whose heights are determined by the left-endpoints of each subinterval. These are $\{x_0,x_1,\cdots,x_{n-1}\}$ . Meanwhile, the right-endpoint approximation involves rectangles with heights determined by the right endpoints, $\{x_1,x_2,\cdots,x_n\}$ .

So, you have

$L=\dfrac{b-a}n\left(f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1})\right)$
$R=\dfrac{b-a}n\left(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n)\right)$

Now let $T$ denote the trapezoidal approximation. The area of each trapezoidal subdivision is given by the product of each subinterval's width and the average of the heights given by the endpoints of each subinterval. That is,

$T=\dfrac{b-a}n\left(\dfrac{f(x_0)+f(x_1)}2+\dfrac{f(x_1)+f(x_2)}2+\cdots+\dfrac{f(x_{n-2})+f(x_{n-1})}2+\dfrac{f(x_{n-1})+f(x_n)}2\right)$

Factoring out $\dfrac12$ and regrouping the terms, you have

$T=\dfrac{b-a}{2n}\left((f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1}))+(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n))\right)$

which is equivalent to

$T=\dfrac12\left(L+R)$

and is the average of $L$ and $R$ .

So the trapezoidal approximation for your problem should be $\dfrac{14+21}2=\dfrac{35}2=17.5\text{ in}^2$

4 0

2 years ago