Answer:
The area of the sector is 3pi/2
Step-by-step explanation:
A sector is that part of a circle bounded by 2 radii and an arc
The circle has an area of 9 pi with a central angle of 60 degrees.
Now the area of the sector is pretty much straight forward to calculate. Since it is a circle, the total angle we have is 360.
Now the sector subtends an angle of 60 degrees at the centre. What this means is that the sector is exactly 1/6 of the circle. meaning that cutting the circle into 6 slices will give the sector.
Thus, the area of the sector is one-sixth the area of the circle.
The area of the sector is thus 1/6 * 9pi = 9pi/6 = 3pi/2 or 3/2 pi
I’m guessing you subtract 78-52 then divide by original which was 52.. so July is 50% warmer.
Mult. f(x) = x^4 by 2 will stretch the graph vertically by a factor of 2.
Thus, eliminate (a) and (b).
Mult. x by (1/4) will stretch the graph horiz. by a factor of 4. Thus, (c) is the correct answer.
Answer:
![y = \frac{32}{3}](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%7B32%7D%7B3%7D)
Step-by-step explanation:
Firstly, move over the negative 3/4 fraction (don't forget to swap the operation i.e subtract to add):
![\frac{y}{8} = \frac{7}{12} + \frac{3}{4}](https://tex.z-dn.net/?f=%5Cfrac%7By%7D%7B8%7D%20%3D%20%5Cfrac%7B7%7D%7B12%7D%20%20%2B%20%5Cfrac%7B3%7D%7B4%7D)
Now, to add the two fractions, simply multiply the numerator and denominator by 3:
![\frac{3*3}{4*3} = \frac{9}{12}](https://tex.z-dn.net/?f=%5Cfrac%7B3%2A3%7D%7B4%2A3%7D%20%3D%20%5Cfrac%7B9%7D%7B12%7D)
Now add this to the other fraction:
![\frac{9}{12} + \frac{7}{12} = \frac{16}{12}](https://tex.z-dn.net/?f=%5Cfrac%7B9%7D%7B12%7D%20%2B%20%5Cfrac%7B7%7D%7B12%7D%20%3D%20%5Cfrac%7B16%7D%7B12%7D)
This can be simplified down by dividing both the numerator and denominator by 4:
![\frac{4}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B3%7D)
Which now simplifies the original equation to:
![\frac{y}{8} = \frac{4}{3}](https://tex.z-dn.net/?f=%5Cfrac%7By%7D%7B8%7D%20%20%3D%20%5Cfrac%7B4%7D%7B3%7D)
Remove the y out of the fraction:
![\frac{1}{8}y = \frac{4}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B8%7Dy%20%3D%20%5Cfrac%7B4%7D%7B3%7D)
Now multiply both sides by 8:
![(\frac{1}{8}y) * 8 = (\frac{4}{3}) * 8](https://tex.z-dn.net/?f=%28%5Cfrac%7B1%7D%7B8%7Dy%29%20%2A%208%20%3D%20%28%5Cfrac%7B4%7D%7B3%7D%29%20%2A%208)
![y = \frac{4*8}{3}](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%7B4%2A8%7D%7B3%7D)
![y = \frac{32}{3}](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%7B32%7D%7B3%7D)
Hope this helps!