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2 years ago

Please help a girl out I'm so confused

Mathematics

2 answers:

Evgesh-ka [11]2 years ago

6 0

Answer:

Girl what kind of MATH IS THISSSSS

Step-by-step explanation:

viktelen [127]2 years ago

5 0

Answer:

Step-by-step explanation:

It appears that the first column is 10(10) and 6(10)

the third column has 6(6) so perhaps top square is 6(10)=60

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H(x) = 9x2 + 1<br> PLSSS HELP

nataly862011 [7]

Answer: 82

Step-by-step explanation:

H=9(-3)^2+1

Simplify both sides of the equation.

h=81+1

81+1 =82

h=82

4 0

2 years ago

Simplify 7N - 2N + 3P + 2P. (a) 5N + 5P (b) 10N + 10P (c)10NP

Yakvenalex [24]

<span>7N - 2N + 3P + 2P

Combine like terms:
7N-2N=5N

3P+2P=5P

Put them together to get :
5N+5P

Final answer:
A</span>

7 0

2 years ago

Read 2 more answers

The coordinates of the midpoint of GH are M(-2, 0), and the coordinates of one endpoint are H(4,-4).

Svetlanka [38]

The coordinate of point S from the giving coordinate point is (-8,4)

<h3>Midpoint of coordinates</h3>

The formula for calculating the midpoint of coordinate point is expressed as:

M(x,y) = {(x₁+x₂)/2, (y₁+y₂)/2}

Determine the measure of the coordinate S
-2 = 4+x₂/2

2(-2) = 4+x₂

x₂ = -4-4

x₂ = -8

Similarly

0 = -4+y₂/2

0(2) = -4+y₂

y₂ = 4

Hence the coordinate of point S from the giving coordinate point is (-8,4)

Learn more on midpoint here: brainly.com/question/5566419

#SPJ1

4 0

1 year ago

For the figures below, assume they are made of semicircles, quarter circles and squares. For each shape, find the area and perim

ICE Princess25 [194]

Answer:

Part a) The area of the figure is $\frac{9}{2}(4+\pi )\ cm^{2}$

Part b) The perimeter of the figure is $3(2+2\sqrt{2}+ \pi)\ cm$

Step-by-step explanation:

Step 1

Find the area of the figure

In this problem we have that

The figure ABC is the half of a square and the other figure is a semicircle

<u>Find the area of the figure ABC</u>

we have

$AB=6\ cm, BC=6\ cm$

The area of the half square ABC is equal to find the area of triangle ABC

$A1=\frac{1}{2}*6*6=18\ cm^{2}$

<u>Find the area of the semicircle</u>

The area of the semicircle is equal to

$A2=\pi r^{2}/2$

we have that

$r=6/2=3\ cm$

substitute

$A2=\pi (3)^{2}/2$

$A2=(9/2) \pi\ cm^{2}$

The area of the figure is equal to

$18\ cm^{2}+(9/2) \pi\ cm^{2}= \frac{9}{2}(4+\pi )\ cm^{2}$

Step 2

Find the perimeter of the figure

The perimeter of the figure is equal to

$P=AB+AC+length\ CB$

we have

$AB=6\ cm$

Applying Pythagoras theorem

$AC=\sqrt{6^{2}+6^{2}}\\AC=6\sqrt{2}\ cm$

Remember that

the circumference of a semicircle is equal to

$C=\frac{1}{2}2\pi r=\pi r$

$r=6/2=3\ cm$

$C=\pi(3)$

$C=3 \pi\ cm$

The perimeter of the figure is equal to

$P=6\ cm+6\sqrt{2}\ cm+3 \pi\ cm$

Simplify

$P=3(2+2\sqrt{2}+ \pi)\ cm$

5 0

3 years ago

Solve for x. Your answer must be simplified. -7x > 10

andre [41]

The answer to this is x < -10/7

5 0

2 years ago