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Lorico [155]
3 years ago
15

A diamond today cost ten dollars more than twice what it cost last year.The sum of the cost (last year and this year) is $2500.

What is the cost of last year diamond? What are the reasonable domain and range?
Mathematics
1 answer:
nadya68 [22]3 years ago
6 0

Answer:

The cost of the diamond last year is x = $ 830

Step-by-step explanation:

Let the cost of diamond last year = x

the cost of diamond present year = y

Given that diamond today cost ten dollars more than twice what it cost last year.

⇒ y = 2 x + 10  ------ (1)

The sum of the cost (last year and this year) is  = $ 2500

⇒ x + y = $ 2500 -------- (2)

Put the value of y in equation (2) from equation (1), we get

⇒ 2 x + 10 + x = $ 2500

⇒ 3 x = 2490

⇒ x = $ 830

& y = 2500 - 830

⇒ y = $ 1670

Therefore the cost of the diamond last year is x = $ 830

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Answer:

The function g(x) is defined as g(x)=-\frac{1}{6}(0.2)^{x-9}.

Step-by-step explanation:

The given function is

f(x)=-(0.2)^x

The function f(x) transformed 9 units right, compressed vertically by factor of 1/6 and reflected across the x-axis.

The transformation of function is defined as

g(x)=kf(x+b)+c

Where, k is vertical stretch, b is horizontal shift and c is vertical shift.

If b>0, then the graph of f(x) shifts b units left and if b>0, then the graph of f(x) shifts b units right.

If c>0, then the graph of f(x) shifts c units upward and if c>0, then the graph of f(x) shifts c units downward.

The value of b is -9 because the graph shifts 9 units right. The value of k is 1/6. If the graph of function f(x)reflect across x-axis, therefore the function is defined as -f(x).

g(x)=\frac{1}{6}(-f(x-9))

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Therefore the function g(x) is defined as g(x)=-\frac{1}{6}(0.2)^{x-9}.

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