Answer:
The proportion of children that have an index of at least 110 is 0.0478.
Step-by-step explanation:
The given distribution has a mean of 90 and a standard deviation of 12.
Therefore mean,
= 90 and standard deviation,
= 12.
It is given to find the proportion of children having an index of at least 110.
We can take the variable to be analysed to be x = 110.
Therefore we have to find p(x < 110), which is left tailed.
Using the formula for z which is p( Z <
) we get p(Z <
= 1.67).
So we have to find p(Z ≥ 1.67) = 1 - p(Z < 1.67)
Using the Z - table we can calculate p(Z < 1.67) = 0.9522.
Therefore p(Z ≥ 1.67) = 1 - 0.9522 = 0.0478
Therefore the proportion of children that have an index of at least 110 is 0.0478
Answer:
The answer is just a drawing of a rectangular prism.
Step-by-step explanation:
Find an image attached for the question required. The user just asked for a draw on the question.
Answer: C
Step-by-step explanation:
is dotted and shaded below, so it represents
.
Also,
is shaded above, so it represents
.
Answer:
40%
Step-by-step explanation:
100%->3200
1%->32
1280÷32= 40 %