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dezoksy [38]
3 years ago
11

How many five digit odd numbers are possible if the leftmost digit cannot be zero?

Mathematics
1 answer:
blagie [28]3 years ago
6 0

Answer:

45000 five digit odd numbers are possible if the leftmost digit cannot be zero.

Step-by-step explanation:

Pls mark the brainliest

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Jax solved an equation and justified his steps as shown below. What reason would justify step 2?
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Answer: The Subtraction Property of Equality

In the problem that Jax solved he subtract 5 from both sides of the equation. This is an example of the subtraction property of equality.

The property states that if you subtract the same amount from both sides of an equation the equation remains the same.
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What's 789,091 rounded to the hundred thousands
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We need to round the number to the nearest hundred throusands.
this means that we will check the number after the poaition of the hundred thousands, if it is 5 or more,then we will add one otherwise we will ignore it and add zeros.
based on this, the number in the position next to the hundred thousands is 8 which mean that we will add one to the hundred thousands positions while all others will become zero.
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