How many five digit odd numbers are possible if the leftmost digit cannot be zero?
1 answer:
Answer:
45000 five digit odd numbers are possible if the leftmost digit cannot be zero.
Step-by-step explanation:
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Answer:
A) SUBTRACT 3x by both sides of the bottom equation.
Answer:
Na20+H20 -> 2NaOH
Step-by-step explanation:
Answer:
32r + 39
Step-by-step explanation:
<u>Step 1: Distribute</u>
4(5 + 8r) + 19
<em>20 + 32r + 19</em>
<em />
<u>Step 2: Combine like terms</u>
<em>32r + 39</em>
<em />
Answer: 32r + 39
If you use the distributive property on (x+y)/3, the result should be:
(x/3) + (y/3)
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B)x=23
y=20
Step-by-step explanation:
