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3 years ago

The cost of a customer's smartphone bill can be modeled by

Mathematics

1 answer:

Sergio039 [100]3 years ago

6 0

Answer:

C = (g + 5)

Step-by-step explanation:

Given the cost of a customers smartphone bill,

C=10g+50

We are required to factor the polynomial.

First, determine the G.C.D of both terms

The GCD of 10g and 50 is 10

Next, we divide each of the term by 10 and balance it by multiplying the expression by 10.

C = 10g + 50

= 10 (10g / 10 + 50/10)

The cost polynomial factored is C=10(g+5).

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The graph of. A fourth degree polynomial function has x-intercept of -3,-2,0 and 2 the point (1,-24) is on the graph of this fun

adelina 88 [10]

Answer: 1+p= 9 and 0.5l + 1.5p = 9.5

Step-by-step explanation:

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3 years ago

There were 2430 Major League Baseball games played in 2009, and the home team won the game in 53% of the games. If we consider t

Ivahew [28]

Answer:

$z=\frac{0.53 -0.5}{\sqrt{\frac{0.5(1-0.5)}{2430}}}=2.958$

$p_v =P(Z>2.958)=0.0015$

So the p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion is significantly higher than 0.5 .

Step-by-step explanation:

1) Data given and notation

n=2430 represent the random sample taken

$\hat p=0.53$ estimated proportion when the home team won the game

$p_o=0.5$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the proportion is higher than 0.5 or 50%:

Null hypothesis: $p\leq 0.5$

Alternative hypothesis: $p > 0.5$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.53 -0.5}{\sqrt{\frac{0.5(1-0.5)}{2430}}}=2.958$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(Z>2.958)=0.0015$

8 0

3 years ago

By the Triangle Inequality Theorem, If two sides of a triangle have lengths of 3 and 7, what are all the possible lengths of the

Charra [1.4K]

If you do
7+3>?
3+?>7
7+?>3
P.S: look at example