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3 years ago

Mai skated x miles, and Clare skatedfarther than that. Write an expression for the distance Clare skated.

Mathematics

1 answer:

Afina-wow [57]3 years ago

3 0

Answer:

Clare skated $(x+y)\ miles.$

Step-by-step explanation:

Given Distance skated by Mai = x miles.

Let the extra distance skated by Clare than Mai be y miles.

Solution,

Total distance skated by Clare = Distance skated by Mai + Extra distance skated by Clare than Mai

Now substituting the values we get;

$Total\ distance\ skated\ by\ Clare = (x+y)\ miles.$

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Put together, Dulcina and Tremaine have 129 total matchbooks. Tremaine's collection has 39 fewer matchbooks in it than Dulcina's

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Let the Dulcina's collection be 'x'

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3 years ago

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3 years ago

Solve this problem please

Anestetic [448]

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3 years ago

Read 2 more answers

Consider the probabilities of people taking pregnancy tests. Assume that the true probability of pregnancy for all people who ta

Valentin [98]

Using conditional probability, it is found that there is a 0.8462 = 84.62% probability that a woman who gets a positive test result is truly pregnant.

<h3>What is Conditional Probability?</h3>

Conditional probability is the probability of one event happening, considering a previous event. The formula is:

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this problem, the events are:

Event A: Positive test result.

Event B: Pregnant.

The probability of a positive test result is composed by:

99% of 10%(truly pregnant).

2% of 90%(not pregnant).

Hence:

$P(A) = 0.99(0.1) + 0.02(0.9) = 0.117$

The probability of both a positive test result and pregnancy is:

$P(A \cap B) = 0.99(0.1)$

Hence, the conditional probability is:

$P(B|A) = \frac{0.99(0.1)}{0.117} = 0.8462$

0.8462 = 84.62% probability that a woman who gets a positive test result is truly pregnant.

You can learn more about conditional probability at brainly.com/question/14398287

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2 years ago