ANSWER:

STEP-BY-STEP EXPLANATION:
We have the following equation:

The inverse is the following (we calculate it by replacing f(x) by x and x by f(x)):

The domain would be the range of the original equation, and it would be the range of values that f(x) could take, which was from -4 to positive infinity, that is, f(x) ≥ -4.
Therefore, the domain is x ≥ -4.
So the correct answer is D.
Answer:

Step-by-step explanation:
To find an equation of a line when given the slope and a point we use the formula

From the question we have

We have the final answer as

Hope this helps you
Answer:
a) 
b) 
c) 
d) 
Step-by-step explanation:
a) 
When factoring a binomial (a polynomial with two terms), what we will be looking for are the terms that are shared between them.
In this problem, it can be seen that both of these terms have and x. This means that we can factor it out to get

b) 
What are the common terms here?
It can be seen that each of these share a 2x, so our factored form would be

c) 
What about this one?
The common factor of this one is 5x, so our factored form would be

d) 
The common factor of this one is
, so our factored form would be
