Answer:
2.48×10^13 miles
Step-by-step explanation:
There are about (365.25 days)(86400 seconds/day) = 31,557,600 seconds in one year. There are 1609.344 meters in one mile. So, the conversion can be written as ...
(4.22 ly) (3×10^8 m/s) (3.15576×10^7 s/yr) / (1.609344×10^3 m/mi)
= 4.22×3×3.15576/1.609344×10^(8+7-3) mi
≈ 24.8×10^12 mi
4.22 light years is about 2.48×10^13 miles
Answer:
The minimum percentage of the commuters in the city has a commute time within 2 standard deviations of the mean is 75%.
Step-by-step explanation:
We have no information about the shape of the distribution, so we use Chebyshev's Theorem to solve this question.
Chebyshev Theorem
At least 75% of the measures are within 2 standard deviations of the mean.
At least 89% of the measures are within 3 standard deviations of the mean.
An in general terms, the percentage of measures within k standard deviations of the mean is given by .
Applying the Theorem
The minimum percentage of the commuters in the city has a commute time within 2 standard deviations of the mean is 75%.