<span>In this situation when using newton's third law, the floor is very rigid and thus when we fall the floor applies
the same amount of force on us with which we were falling on it. The rigidness of the concrete floor makes it difficult for it to absorb some of our force. On the other hand sand is not rigid on impact sine it changes its shape while it absorbs a
large amount of our falling force and a small fraction of this
force is applied on is. That is why we don't get hurt</span>
Pluto was discovered by the astronomer Clyde Tombaugh in February 1930. It was given the status of the ninth planet of the solar system.
As telescopes, particularly in on satellites, improved, more objects were discovered which caused a problem that they were quite small and some astronomers didn't think they qualified as being planets.
The International Astronomical Union (IAU) had a vote which was very close. They defined three criteria which a planet must satisfy.
It must be large enough for gravity to overcome structures of materials and make it spherical. Most bodies are flattened spheroids due to rotation.
It must orbit the Sun.
It must have cleared its orbit of other bodies other than moons.
The IAU created a new definition of an object called a dwarf planet which only satisfies the first two criteria. Pluto fails the third criterion, so it was demoted to a dwarf planet.
Many people, including myself, still consider Pluto to be the ninth planet.
To be pedantic, Jupiter has a lot of asteroids in its orbit at its two Lagrange points. They are called trojan asteroids. So, this means that Jupiter fails the IAU's third criterion and should be a dwarf planet, which it is certainly not!
Given the values to proceed to solve the exercise, we resort to the solution of the exercise through differential equations.
The problem can be modeled through a linear equation, in the form:
With the initial conditions as,
Where Q(t) is the charge.
<em>The general solution of a linear equation is given as:</em>
<em>
</em>
Applying this definiton in our differential equation we have that
To find b and a we use the first equation and find the roots:
Then we have
To find the values of the Constant we apply the initial conditions, then
And for the derivate:
We have a system of 2x2:
Solving we have:
The we can replace at the equation and we have that the Charge at any moment is given by,
If we obtain the derivate we find also the Current, then
Base in your question that ask for the distance that the remote control would extend beyond the edge where as a remote control is 22cm long and has a mass of 0.08kg =, base on my calculation the answer would be 1.27cm i hope you understand my answer
