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1 year ago

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If 36 grams of water is to be heated from 24.0°C to 48°C to make a cup of tea, how much heat must be added? The specific heat of

water is 4.18

1 answer:

Vinvika [58]1 year ago

3 0

We will have the following:

$\begin{gathered} Q=mc\Delta T\Rightarrow Q=(36)(4.18)(48-24) \\ \\ \Rightarrow Q=3611.52 \end{gathered}$

So, the heat to add is 3611.52 Joules.

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<h2>14.52 J</h2>

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We have the final answer as

<h3>14.52 J</h3>

Hope this helps you

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