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3 years ago

The vibrations along a transverse wave move in a direction _________.

Physics

1 answer:

GrogVix [38]3 years ago

5 0

Answer: perpendicular to it oscillations.

Explanation: A transverse wave is a wave whose oscillations is perpendicular to the direction of the wave.

By perpendicular, we mean that the wave is oscillating on the vertical axis (y) of a Cartesian plane and the vibration is along the horizontal axis (x) of the plane.

Examples of transverse waves includes wave in a string, water wave and light.

Let us take a wave in a string for example, you tie one end of a string to a fixed point and the other end is free with you holding it.

If you move the rope vertically ( that's up and down) you will notice a kind of wave traveling away from you ( horizontally) to the fixed point.

Since the oscillations is perpendicular to the direction of wave, it is a transverse wave

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Much power does a 10 Ohm bulb have in a series circuit with a battery of 12V and nothing else in the the circuit?

Sedaia [141]

Answer:

it will be d) 14.4W

Explanation:

potential difference (v) = 12 volts

resistance (r) = 10 ohms

now, we know

=》

$power = \frac{v {}^{2} }{r}$

=》

$power \: = \frac{12 {}^{2} }{10}$

=》

$power = \frac{144}{10}$

=》

$power = 14.4 \: watt$

8 0

3 years ago

A 5.6 cm diameter parallel-plate capacitor has a 0.58 mm gap. What is the displacement current in the capacitor if the potential

BARSIC [14]

Answer:

$1.88\cdot 10^{-5} A$

Explanation:

The capacitance of a parallel plate capacitor is given by:

$C=\frac{\epsilon_0 A}{d}$ (1)

where

$\epsilon_0$ is the vacuum permittivity

A is the area of the plates

d is the separation between the plates

The charge stored on the capacitor is given by

$Q=CV$ (2)

where C is the capacitance and V is the voltage across the capacitor.

The displacement current in the capacitor is given by

$J=\frac{Q}{t}$ (3)

where t is the time elapsed

Substituting (1) and (2) into (3), we find an expression for the displacement current:

$J=\frac{CV}{t}=\frac{\epsilon_0 A}{d} \frac{V}{t}$

where we have

$A=\pi (\frac{d}{2})^2=\pi (\frac{0.056 m}{2})^2=2.46\cdot 10^{-3} m^2$

$d = 0.58 mm = 5.8\cdot 10^{-4} m$

$\frac{V}{t}=500,000 V/s$

Substituting into the equation, we find

$J=\frac{(8.85\cdot 10^{-12} F/m)(2.46\cdot 10^{-3} m^2)}{5.8\cdot 10^{-4}m}(500,000 V/s)=1.88\cdot 10^{-5} A$

6 0

3 years ago

What is the voltage of the power source if a motor with a resistance of 20 2 draws a

Lady_Fox [76]

Answer:

190v I believe

hope this helped a little and if it did pls mark brainiest :)

8 0

3 years ago

A body of mass 100g moving with a velocity of 10.0m/s collides with a wall .if after the collision it moves with a velocity of 2

ch4aika [34]

Answer:

-1.2 kg - m/s

Explanation:

$\pink{\frak{Given}}\begin{cases}\textsf{ A body of mass 100g moving with a velocity of 10.0m/s collides with a wall .}\\\textsf{ After the collision it moves with a velocity of 2.0m/s in the opposite direction.}\end{cases}$

And we need to find out the change in momentum of the body . Here ,

velocity before collision (u) = 10m/s
velocity after collision (v) = 2m/s .

We know that momentum is defined as amount of motion contained in a body . Mathematically ,

$\sf\longrightarrow momentum (p)= mass(m) * velocity(v)$

Therefore change in momentum will be,

$\sf\longrightarrow \triangle p = mv - mu$

Since the direction of velocity changes after the collision , the velocity will be -2m/s .

$\sf\longrightarrow \Delta p = 100g( -2m/s -10m/s) \\$

$\sf\longrightarrow \Delta p =\dfrac{100}{1000}kg ( -12m/s) \\$

$\sf\longrightarrow \Delta p = 0.1 kg * -12m/s \\$

$\sf\longrightarrow \boxed{\bf \Delta p = -1.2 \ kg-m/s} \\$

7 0

2 years ago

Please fill in question 3 (i) fast please science homework

Kitty [74]

The answers are 3.3kWh, 1.2kWh, and 120kWh.

Multiply the amount of kW used per hour by the amount of time it was powered and you receive your answer.

6 0

3 years ago