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Crazy boy [7]
3 years ago
13

An amusement park charges 5$ for admission and 2$ for each ride write an expression for the total cost of admission and r rides

How many Rides Can He Ride With 16$??? I NEED THIS DONE PEOPLE ;C

Mathematics
1 answer:
sashaice [31]3 years ago
5 0
He can ride 5 rides in this problem

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On a bird-watching trip, Mei and Jackie counted 68 birds.
defon

Answer:

The answer is 70% if you round it.

Step-by-step explanation:

45 out of 68 is 66 but if you're rounding it the answer is 70%.

5 0
2 years ago
Find the indicated limit, if it exists.
Paha777 [63]
The limit is the y value that the graph approaches from both sides as x approaches the target limit

it they approach different values from the left and right sides, the limit does not exist

we want to find the limit as x approaches 5

we are given that f(x)=5-x for x<5 and f(5)=8 and f(x)=x+3 for x>5

evaluate them all for f(5)
f(x)=5-x
f(5)=5-5
f(5)=0

f(5)=8

f(x)=x+3
f(5)=5+3
f(5)=8

it approaches 0 and 8 from both sides
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8 0
2 years ago
23 degrees 20’48 is the same as _degrees.
allochka39001 [22]

Answer:

\large\boxed{23^o20'48''=\left(23\dfrac{26}{75}\right)^o}

Step-by-step explanation:

\text{We know:}\\\\1^o=60'\to1'=\left(\dfrac{1}{60}\right)^o\\\\1'=60''\to1^o=(60)(60'')=3600''\to1''=\left(\dfrac{1}{3600}\right)^o\\\\23^o20'48''\\\\20'=\left(\dfrac{20}{60}\right)^o=\left(\dfrac{1}{3}\right)^o\\\\48''=\left(\dfrac{48}{3600}\right)^o=\left(\dfrac{1}{75}\right)^o\\\\\text{Therefore}\\\\23^o20'48''=23^o+20'+48''=23^o+\left(\dfrac{1}{3}\right)^o+\left(\dfrac{1}{75}\right)^o\\\\=\left(23+\dfrac{1\cdot25}{3\cdot75}+\dfrac{1}{75}\right)^o=\left(23+\dfrac{25}{75}+\dfrac{1}{75}\right)^o=\left(23\dfrac{26}{75}\right)^o

4 0
3 years ago
What are the value(s) for K? 7K^3=56 Please show your work
Phoenix [80]
I hope this helps you

6 0
3 years ago
jocelyn mowed a lawn that is 722 1/2 square yards. Her brother mowed a lawn that is 842 18/25 square yards. How many square yard
cricket20 [7]
Together they mowed 1565 11/50 square yards. You have to make the fractions have same denominators so you can add, after fixing the denominators, just add. 

7 0
3 years ago
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