The missing coordinates of the parallelogram is (m + h, n).
Solution:
Diagonals of the parallelogram bisect each other.
Solve using mid-point formula:

Here 


<u>To find the missing coordinate:</u>
Let the missing coordinates by x and y.
Here 



Now equate the x-coordinate.

Multiply by 2 on both sides of the equation, we get
m + h = x
x = m + h
Now equate the y-coordinate.

Multiply by 2 on both sides of the equation, we get
n = y
y = n
Hence the missing coordinates of the parallelogram is (m + h, n).
Answer: I can’t solve (x+2)^2/64+(y-1)^2/81=1 but I solve (x+2)^2/64+(y-1)^2/81 it the same thing but I take out the =1
Step-by-step explanation: look at the picture and you see me answer, hope this help:)
- The zeros of the function are 0 and 2
- The multiplicity is the power to which the factors are raised. The multiplicities of the function are 1 and 3.
<h3>Zeros and multiplicities of functions</h3>
Given the function 
The zeros of the function is at the point where y = 0

Hence the zeros of the function are 0 and 2
The multiplicity is the power to which the factors are raised. The multiplicities of the function are 1 and 3.
Learn more on zeros and multiplicity here: brainly.com/question/11314797
Answer:
The y-coordinate of the solution is -5.
Step-by-step explanation:
I graphed the equations on the graph below to find the solution of the system.
If this answer is correct, please make me Brainliest!
I don't know if this is right, but I'm pretty sure it's B.