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gizmo_the_mogwai [7]
2 years ago
13

Which is different?

Mathematics
1 answer:
Alja [10]2 years ago
7 0

A) Solve 3x+6y=24 for x.

Subtracting 6y from both sides, we get

3x+6y-6y=24-6y

3x = -6y+24

Dividing both sides by 3, we get

\frac{3x}{3} = \frac{-6y}{3} +\frac{24}{3}

x= -2y + 8

b) Solve 24−3x=6y for x.

Subtracting 24 from both sides, we get

24-24−3x=6y-24

-3x = 6y -24.

Dividing both sides by -3, we get

\frac{-3x}{-3} =\frac{6y}{-3} -\frac{24}{-3}

x= -2y + 8.

c) Solve 6y=24−3x for y in terms of x.

Dividing both side by 6.

\frac{6y}{6} =\frac{24}{6}- \frac{3x}{6}

y= -\frac{1}{2}x+4

d) Solve 24−6y=3x for x in terms of y.

Dividing both sides by 3, we get

\frac{24}{3} - \frac{6y}{3} = \frac{3x}{3}

8 - 2y = x.

x = -2y +8

<h3>Therefore, x=-2x+8 and y=-\frac{1}{2}x+4.</h3>
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__

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Step-by-step explanation:

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What is the range of the relation in the table below ???
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