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11111nata11111 [884]
2 years ago
5

Which of the following numbers is between 0.08 and 0.4?

Mathematics
1 answer:
Delicious77 [7]2 years ago
3 0

Answer:

C

Step-by-step explanation:

the numbers between 0.08 and 0.4 are:

0.09, 0.10, 0.11, 0.12, 0.13, 0.14, 0.15, .16, 0.17, 0.18, 0.19, 0.20, 0.21, 0.22, 0.23, 0.24, 0.25, 0.26, 0.27, 0.28, 0.29, 0.30, 0.31, 0.32, 0.33, 0.34, 0.35, 0.36, 0.37, 0.38, 0.39

I bolded the number closest to your answer choices, hope this helps!

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1600m = 1600 ÷ 1000 = 1.6 km

Answer: 1.6 km
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Val needs to find the area enclosed by the figure. The figure is made by attaching semicircles to each side of a 58​-by-58 squar
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Answer:

We need to find the area of the semicircles + the area of the square.

The area of a square is equal to the square of the lenght of one side.

As = L^2 = 58m^2 = 3,364 m^2

Now, each of the semicircles has a diameter of 58m, and we have that the area of a circle is equal to:

Ac = pi*(d/2)^2 = 3.14*(58m/2)^2 = 3.14(27m)^2 = 2,289.06m^2

And the area of a semicircle is half of that, so the area of each semicircle is:

a =  (2,289.06m^2)/2 = 1,144.53m^2

And we have 4 of those, so the total area of the semicircles is:

4*a = 4* 1,144.53m^2 = 4578.12m^2

Now, we need to add the area of the square 3,364 m^2 + 4578.12m^2 = 7942.12m^2

This is nothing like the provided anwer of Val, so the numbers of val may be wrong.

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3 years ago
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4. Simplify the expression 9c + 6 -4c -3<br><br> A.13c + 9<br> B. 13c+ -3<br> C.5c + 9<br> D. 5c + 3
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Answer:

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Step-by-step explanation:

7 0
3 years ago
.11 A machine produces metal pieces that are cylindrical in shape. A sample of pieces is taken, and the diameters are found to b
Troyanec [42]

Answer:

The 99% confidence interval for the mean diameter of pieces from this machine is between 0.93 and 1.07.

Step-by-step explanation:

Sample mean:

Sum of all values divided by the number of values. So

M = \frac{1.01+0.97+1.03+1.04+0.99+0.98+0.99+1.01+1.03}{9} = 1

Sample standard deviation:

Square root of the sum of the differences between each value and the mean, divided by the 1 less than the sample size. So

s = \sqrt{\frac{(1.01-1)^2+(0.97-1)^2+(1.03-1)^2+(1.04-1)^2+(0.99-1)^2+(0.98-1)^2+(0.99-1)^2+(1.01-1)^2+(1.03-1)^2}{8}} = 0.0657

Confidence interval:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 9 - 1 = 8

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 8 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.99}{2} = 0.995. So we have T = 3.355

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 3.355\frac{0.0657}{\sqrt{9}} = 0.07

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 1 - 0.07 = 0.93

The upper end of the interval is the sample mean added to M. So it is 1 + 0.07 = 1.07

The 99% confidence interval for the mean diameter of pieces from this machine is between 0.93 and 1.07.

7 0
2 years ago
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