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3 years ago

PLZZ HELPP!! Find the perimeter of the following polygon.

Mathematics

2 answers:

hodyreva [135]3 years ago

4 0

Answer:

43in

Step-by-step explanation:

Perimeter = sum of the sides

Perimeter = 11 + 10 + 10 + 12 = 43

Vilka [71]3 years ago

3 0

Answer:

p = 43

Step-by-step explanation:

Perimeter = all side lengths added

Perimeter = 10 + 10 + 11 + 12

Perimeter = 43

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Which equations have a greater unit rate than the rate represented in the table?

In-s [12.5K]

Table slope = (4-2)/((6-3) = 2/3

A. 5/7 > 2/3
B. 3/5 < 2/3
C. 1/3 < 2/3
D. 7/9 > 2/3
E. 7/11< 2/3

3 0

3 years ago

Read 2 more answers

Put brackets in the calculation below to make it correct. 15 - 4 x 2 + 1 = 3

bagirrra123 [75]

If you put brackets around (2+1), your method of working is:
1) 15-4*(2+1)=3
2) 15-4*3=3
3) 15-12=3
You don't need any more brackets, as the BIDMAS (brackets, Indices, division, multiplication, addition, subtraction) rule does the rest of the job for you.
The answer is therefore: 15-4*(2+1)=3

3 0

3 years ago

100 random students are surveyed outside of the student center on campus. Let V denote that the student has a Visa credit card a

mote1985 [20]

Answer:

(a) The value of P (M | V) is 0.30.

(b) The value of $P (M^{c} | V)$ is 0.70.

(d) The value of $P(V^{c}|M)$ is 0.625.

Step-by-step explanation:

It is provided that,

V = a student has a Visa card

M = a student has a Master card

N = 100, n (V) = 40, n (M) = 32 and n (V ∩ M) = 12.

The probability of a student having visa card is:

$P(V) = \frac{n(V)}{N}= \frac{40}{100}=0.40$

The probability of a student having master card is:

$P(M) = \frac{n(M)}{N}= \frac{32}{100}=0.32$

The probability of a student having visa card and a master card is:

$P(V\cap M) = \frac{n(V\cap M)}{N}= \frac{12}{100}=0.12$

The conditional probability of an event, say A, given that another event, say B, has already occurred is,

$P(A|B)=\frac{P(A\cap B)}{P(B)}$

(a)

Compute the probability that a student has a master card given that he/she has a visa card also, i.e. P (M | V) as follows:

$P(M|V)=\frac{P(V\cap M)}{P(V)} =\frac{0.12}{0.40}=0.30$

Thus, the value of P (M | V) is 0.30.

(b)

Compute the probability that a student does not have a master card given that he/she has a visa card also, i.e. $P (M^{c} | V)$ as follows:

$P (M^{c} | V)=1-P(M|V)=1-0.30=0.70$

Thus, the value of $P (M^{c} | V)$ is 0.70.

(c)

Compute the probability that a student has a visa card given that he/she has a master card also, i.e. P (V | M) as follows:

$P(V|M)=\frac{P(V\cap M)}{P(M)} =\frac{0.12}{0.32}=0.375$

Thus, the value of P (V | M) is 0.375.

(d)

Compute the probability that a student does not have a visa card given that he/she has a master card also, i.e. $P(V^{c}|M)$ as follows:

$P(V^{c}|M)=1-P(V|M)=1-0.375=0.625$

Thus, the value of $P(V^{c}|M)$ is 0.625.

8 0

3 years ago

Data on pull-off force (pounds) for connectors used in an automobile engine application are as follows:

hjlf

Answer:

a) 75.62

b) 75.2

Step-by-step explanation:

Data provided:

79.9,75.1,78.2,74.1,73.9,75.0,77.6,77.3,73.8,74.6,75.5,74.0,74.7,75.9,72.6,73.8,74.2,78.1,75.4,76.3,75.3,76.2,74.9,78.0,75.1,76.8

Sum = 1966.3

Total number of observations, n = 26

a) Mean is given as:

Mean = $\frac{\textup{Sum of all observations}}{\textup{Total number of observations}}$

Mean = $\frac{\textup{1966.3}}{\textup{26}}$

Mean = 75.62

b) For value that separates the weakest 50% of the connectors i.e median or the 50th percentile

Arranging the data in ascending order:

72.6, 73.8, 73.8, 73.9, 74, 74.1, 74.2, 74.6, 74.7, 74.9, 75, 75.1, 75.1, 75.3, 75.4, 75.5, 75.9, 76.2, 76.3, 76.8, 77.3, 77.6, 78, 78.1, 78.2, 79.9

i = $\frac{\textup{n}}{\textup{2}}$

i = $\frac{\textup{26}}{\textup{2}}$ = 13

When the number of observations is even the formula for median is:

$Median = \frac{\frac{n}{2}+\frac{n+2}{2}}{2}$

$Median = \frac{\frac{26}{2}+\frac{26+2}{2}}{2}$

$Median = \frac{13th+14th}{2}$

$Median = \frac{75.1+75.3}{2}$

Median = 75.2

7 0

3 years ago

The value of a is negative in the equation y = ax 2 + bx + c. true or false

ziro4ka [17]

The given equation y=a $x^{2}.+bx+C$ represents a degree 2 equation .The equation drawn on a graph represents a parabola.The value of a decides if the parabola will open up or down.It can be negative or a positive number but not 0.

If a=0 then equation will represent a straight line .

If a is negative parabola opens down.If a is positive parabola open up.

The value of a is only negative is False.

5 0

3 years ago

Read 2 more answers