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3 years ago

Multiply (8.42×10^3)(5×10^2) in scientific notation

Mathematics

1 answer:

Liono4ka [1.6K]3 years ago

3 0

4.21 x 10<span>6 is the answer

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What is the solution to this equation? 4x+x-15+3-8=13

deff fn [24]

Answer:

x = 33/5

Step-by-step explanation:

4x+x-15+3-8=13

Combine like terms

5x -20 = 13

Add 20 to each side

5x-20+20 = 13+20

5x =33

Divide by 5

5x/5 = 33/5

x = 33/5

3 0

4 years ago

Need help plz Compare using <, >, or =.

jek_recluse [69]

Meanings of inequalities :

< less than
> more than
= equal

convert both fractions to their common denominators , which is 40.

7/2/5 = 7/16/40
7/3/8 = 7/15/40

as you can see, 7/2/5 is bigger. thus the answer is > .

3 0

3 years ago

Can someone please help me here! Tell me the answer I’ll give a brainliest to the one who is right!

Anton [14]

Answer:

False

Step-by-step explanation:

The equation is equal to -24 = -19. That's not true

3 0

3 years ago

Read 2 more answers

What is the standard deviation of the following data set?

tia_tia [17]

Answer:

D. 14.32

Step-by-step explanation:

The formula for standard deviation is:

$SD = \sqrt{\frac{\sum | x-\mu|^2}{N}}$

The mean μ is 33.

The (x minus μ) squared are 361, 49, 49, 361 respectively.

So that the SD = $\sqrt{\frac{820}{4}} \approx 14.31782...$

4 0

3 years ago

What's the next number? 0 , 1/3 , 1/2 , 3/5 , 2/3

madam [21]

Answer:

The next number of the series 0, 1/3, 1/2, 3/5, and 2/3 is 5/7

Step-by-step explanation:

The given numbers are;

0, 1/3, 1/2, 3/5, and 2/3

The number sequence is formed adding $\dfrac{1}{\left (\dfrac{n^2 + n}{2} \right ) }$ to each (n - 1)th term to get the nth term number in the sequence, with the first term equal to 0, as follows;

For the 2nd term, the (n - 1)th term is 0, and n = 2, gives;

The

$0 +\dfrac{1}{\left (\dfrac{2^2 + 2}{2} \right ) } = 0 + \dfrac{1}{3} = \dfrac{1}{3}$

For the 3rd term, the (n - 1)th term is 1/3, and n = 3, gives;

$\dfrac{1}{3} +\dfrac{1}{\left (\dfrac{3^2 + 3}{2} \right ) } = \dfrac{1}{3} + \dfrac{1}{6} = \dfrac{1}{2}$

For the 4th term, the (n - 1)th term is 1/2, and n = 4, gives;

$\dfrac{1}{2} +\dfrac{1}{\left (\dfrac{4^2 + 4}{2} \right ) } = \dfrac{1}{2} + \dfrac{1}{10} = \dfrac{3}{5}$

For the 5th term, the (n - 1)th term is 3/5, and n = 5, gives;

$\dfrac{3}{5} +\dfrac{1}{\left (\dfrac{5^2 + 5}{2} \right ) } = \dfrac{3}{5} + \dfrac{1}{15} = \dfrac{2}{3}$

For the next or 6th term, the (n - 1)th term is 2/3, and n = 6, gives;

$\dfrac{2}{3} +\dfrac{1}{\left (\dfrac{6^2 + 6}{2} \right ) } = \dfrac{2}{3} + \dfrac{1}{21} = \dfrac{15}{21} = \dfrac{5}{7}$

The next number of the series 0, 1/3, 1/2, 3/5, and 2/3 = 5/7.

6 0

3 years ago