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bazaltina [42]
3 years ago
6

How can you change the equation y = mx + b to shift the graph down?

Mathematics
1 answer:
IrinaK [193]3 years ago
8 0

Step-by-step explanation: To shift the graphs up and down on the coordinate system, you need to manipulate or change the y-intercepts.

The y-intercept is just the constant term in the equation.

As long as the slopes remain the same, the graphs can be

translated up or down by changing the constant value.

Take a look at these lines graphed below.

Notice that y = x + 11 is the same as y = x + 4 but

y = x + 11 is translated 7 units down to get y = x + 4.

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1/2(4x-2)-2/3(6x+9) greater or equal to 4
Simora [160]
1/2(4x-2)-2/3(6x+9)
(2x-1)-(4x+6)
2x-1-4x+62x-4x-1+6
-2x+5=2.5
So I believe that it is greater than 4
8 0
3 years ago
Nerisa has 5 pink bow, 1 Blue bow ,and 4 Purple bows in a box. She will Randomly choose 1 bow from the box
4vir4ik [10]
The answer is A. Hope this helps

3 0
3 years ago
30 points I'm struggling Find the equations of each line and show all of your work. (1, 5) (2, 6) (1, 1) (3, -8) (2, -3) (5, -2)
Free_Kalibri [48]

Answer:

1.(1,5) and (2,6) , 6-5/2-1=1/1 m=1 ,y=1x+b

5=1(1)+b 4=b

y=x+4

2.(1,1) and (3,-8) -8-1/3-1=-9/2 m=-9/2 ,y=-9/2x+b

1=-9/2(1)+b b=11/2

y=-9/x+11/2

3.(2.-3) and (5,-2) m=1/3 ,y=1/3x+b

-3=1/3(2)+b -3=2/3+b

-3-2/3=b

 b=-11/3

y=1/3x-11/3

4.(2,5)and (4,3) m=-1 y=-1x+b

5=-1(2)+b 5=-2+b

5+2=b

b=7

y=-1x+7

6.(-3,-5) and (-1,-3) m=2/2=1 y=1x+b

-5=1(-3)+b -5=-3+b

-5+3=b

-2=b

y=1x-2

Step-by-step explanation:

7 0
3 years ago
Simplify 8 + 3{x - 2[x + 5(x + 3)]}.<br><br> -33x + 82<br> 33x - 82<br> -33x - 82
77julia77 [94]

Answer:

<h2>-33x - 82</h2>

Step-by-step explanation:

Use

PEMDAS:

P      Parentheses first

E Exponents (ie Powers and Square Roots, etc.)

MD Multiplication and Division (left-to-right)

AS Addition and Subtraction (left-to-right)

and the distributive property a(b + c) = ab + ac.

1)\qquad5(x+3)=5x+15\\\\2)\qquad x+5(x+3)=x+5x+15=6x+15\\\\3)\qquad2[x+5(x+3)]=2(6x+15)=12x+30\\\\4)\qquad x-2[x+5(x+3)]=x-(12x+30)=x-12x-30=-11x-30\\\\5)\qquad3\{x-2[x+5(x+3)]\}=3(-11x-30)=-33x-90\\\\6)\qquad8+3\{x-2[x+5(x+3)]\}=8+(-33x-90)=-33x-82

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3 years ago
What goes into 9 12 6 3 and 4
Leokris [45]
It could possibly be one.
3 0
3 years ago
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