K=37
You multiply 13 and 3 and you get 39. You then subtract 2 from 39 to get K.
Answer:
Ok, as i understand it:
for a point P = (x, y)
The values of x and y can be randomly chosen from the set {1, 2, ..., 10}
We want to find the probability that the point P lies on the second quadrant:
First, what type of points are located in the second quadrant?
We should have a value negative for x, and positive for y.
But in our set; {1, 2, ..., 10}, we have only positive values.
So x can not be negative, this means that the point can never be on the second quadrant.
So the probability is 0.
Answer:
so i dont know about this one but i think it is -45
Step-by-step explanation:
Answer:
i have no idea sorry but there are way tooooooooooo many words in this question so it doesnt really make much sence especially the bottom part if the question.