Convert 1 Iinto an improper fraction.

Mathematics

1 answer:

FromTheMoon [43]3 years ago

3 0

Answer:

only mixed number can be changed into improper fraction according to my khowlage of grade7

Step-by-step explanation:

thank you

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|×|=×<br>is the absolute value of x always, sometimes, or never x

il63 [147K]

Answer:

Sometimes

Step-by-step explanation:

I’ll give you an example so you can understand:

Let’s say x is 4. So plug 4 into the problem:

|4|=4 → This is a very true statement, where the absolute value of 4 is equal to 4.

Now, let’s say x is -7. So plug -7 into the problem:

|-7|=-7 → This is a false statement because it’s saying that the absolute value of -7 is -7 which is very untrue.

So |x|=x only works for positive numbers, but not negative numbers. Therefore, |x|=x is the absolute value of x <u>sometimes.</u>

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Hope this helps and answers your question! :)

6 0

3 years ago

If fernando paid $450 for a netbook that was 75% of the original price what was the original price

Ilya [14]

Answer: 600 dollars

Step-by-step explanation: 75% is 3/4 so you divide 450 by 3 to get 150. So you know for 1/4 the price is 150 dollars. Now that you know that you can multiply 150 4 times to get the full amount. 150*4=600

5 0

3 years ago

Plzz help Solve for x x ÷3 3/10 =2 2/5

Svet_ta [14]

Answer:

$\huge\boxed{x=7\dfrac{23}{25}}$

Step-by-step explanation:

$x\div3\dfrac{3}{10}=2\dfrac{2}{5}\\\\\text{convert the mixed number to the impropper fraction}\\\\3\dfrac{3}{10}=\dfrac{3\cdot10+3}{10}=\dfrac{33}{10}\\\\2\dfrac{2}{5}=\dfrac{2\cdot5+2}{5}=\dfrac{12}{5}\\\\x\div\dfrac{33}{10}=\dfrac{12}{5}\\\\x\times\dfrac{10}{33}=\dfrac{12}{5}\qquad\text{multiply both sides by}\ \dfrac{33}{10}\\\\x\times\dfrac{10\!\!\!\!\!\diagup}{33\!\!\!\!\!\diagup}\times\dfrac{33\!\!\!\!\!\diagup}{10\!\!\!\!\!\diagup}=\dfrac{12}{5}\times\dfrac{33}{10}\\\\x=\dfrac{396}{50}$