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professor190 [17]
2 years ago
11

80 1/4 is 5% of what number

Mathematics
1 answer:
MAXImum [283]2 years ago
8 0

Answer: 80 1/4 is 5% of 1605

Step-by-step explanation:

5 percent of some number = 80.25

let x = some number

\frac{5}{100} *x = 80.25

=\frac{100}{5} *\frac{5}{100} *x=80.25*\frac{100}{5}

=x=80.25*20

=x=1605

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Answer:

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Step-by-step explanation:

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2 years ago
Evaluate the expression 2s for s=9
Bas_tet [7]
Hello, there!


If s = 9, then 2s = 2 * 9

2 * 9 = 18

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6 0
3 years ago
Use a t-distribution to answer this question. Assume the samples are random samples from distributions that are reasonably norma
Nataliya [291]

Answer:

The degrees of freedom is 11.

The proportion in a t-distribution less than -1.4 is 0.095.

Step-by-step explanation:

The complete question is:

Use a t-distribution to answer this question. Assume the samples are random samples from distributions that are reasonably normally distributed, and that a t-statistic will be used for inference about the difference in sample means. State the degrees of freedom used. Find the proportion in a t-distribution less than -1.4  if the samples have sizes 1 = 12 and n 2 = 12 . Enter the exact answer for the degrees of freedom and round your answer for the area to three decimal places. degrees of freedom = Enter your answer; degrees of freedom proportion = Enter your answer; proportion

Solution:

The information provided is:

n_{1}=n_{2}=12\\t-stat=-1.4

Compute the degrees of freedom as follows:

\text{df}=\text{Min}.(n_{1}-1,\ n_{2}-1)

   =\text{Min}.(12-1,\ 12-1)\\\\=\text{Min}.(11,\ 11)\\\\=11

Thus, the degrees of freedom is 11.

Compute the proportion in a t-distribution less than -1.4 as follows:

P(t_{df}

                      =P(t_{11}>1.4)\\\\=0.095

*Use a <em>t</em>-table.

Thus, the proportion in a t-distribution less than -1.4 is 0.095.

8 0
3 years ago
List the first three multiples of both 3 and 9.
tia_tia [17]

Answer:

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hope this helps u

8 0
3 years ago
Read 2 more answers
This question relates to concepts covered in Lectures 1 &amp; 2. You can use any of the excel files posted to work through the q
liubo4ka [24]

Answer:

mean of this demand distribution = 100

Step-by-step explanation:

To find the mean of this demand distribution;

Mean = Expected vale = E[x]

for discrete provability function,

we say E[x] = ∑(x.p(x))

x     p(x)     x.p(x)

10     0.1     1

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60    0.4    24

90    0.7    63

∴ ∑(x.p(x)) = ( 1 + 12 + 24 + 63 )

∑(x.p(x)) = 100

7 0
3 years ago
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