Question

If the measure of FGH IS 64º and the measure of EGD is (4x+8), what is the value of x?

Answer 1

$\\ \sf\longmapsto 4x+8=64$

$\\ \sf\longmapsto 4x=64-8$

$\\ \sf\longmapsto 4x=56$

$\\ \sf\longmapsto x=\dfrac{56}{4}$

$\\ \sf\longmapsto x=14$