Personally I'd solve this inequality for y first: y < x-3.
That immediately eliminates (6,2) and (2,6).
Starting from y < x-3 and letting 2 sub for x and -1 sub for y, is the following true or false?
-1 < 2 -3 NO. -1 < -1 is false. Was there a fourth answer choice?
Answer:
D. Minimum at (3, 7)
Step-by-step explanation:
We can add and subtract the square of half the x-coefficient:
y = x^2 -6x +(-6/2)^2 +16 -(-6/2)^2
y = (x -3)^2 +7 . . . . . simplify to vertex form
Comparing this to the vertex for for vertex (h, k) ...
y = (x -h)^2 +k
We find the vertex to be ...
(3, 7) . . . . vertex
The coefficient of x^2 is positive (+1), so the parabola opens upward and the vertex is a minimum.
Answer:
0.064
Step-by-step explanation:
( 0.4) ^3
Solution :
( 0.4) ^3
= 0.4 x 0.4 x 0.4
= 0.064
Answer:
i dunno sorry
Step-by-step explanation: