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dexar [7]
2 years ago
8

Class A has 13 pupils and class B has 16 pupils.

Mathematics
1 answer:
andre [41]2 years ago
7 0

Answer:

ok so we can just add 20 + 45 then divide by 2

20+45=65/2=32.5

32.5

Hope This Helps!!!

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In brianna's homeroom class, 9% of the students were born in march and 40% of the students have a blood type of o+.
Firlakuza [10]

Answer:

3.6%

Step-by-step explanation:

Because the two events are independent, their probabilities are multiplied, so the probability of a student being born in March and having a blood type of O+ is 9% * 40% = 0.09 * 0.40 = 0.036 = 3.6%

3 0
2 years ago
Simplify -4(-9p + -3) +2(-2p + 6)
zalisa [80]

Answer:32p+24

Step-by-step explanation:

-4(-9p + -3) +2(-2p + 6)

36p+12-4p+12

32p+24

Hope it helped you

4 0
3 years ago
Please answer this, ILL MARK YOU THE BRAINLIEST
vova2212 [387]

Answer: the answer is (2,-4) if that's not the answer then can u post a full picture of the question

Step-by-step explanation:

4 0
3 years ago
Locate the point on the line segment between A(3, -5) and B(13, -15) given that the point is 4/5 of the way from A to B. Show yo
SVETLANKA909090 [29]

Answer:

C ( 11 , -11 )

Step-by-step explanation:

Solution:-

We are given two points in the cartesian coordinate system as:

                   A ( 3 , -5 )              B ( 13 , -15 )

The point C lies on the line segment from A to B. The ratio of segment given is:

                              AC / AB = 4 / 5

To solve such type of problems. We will use vector equation of line AC.

To form a vector equation of line representing AB. We will first determine the direction vector ( d ) that is parallel to the line AB as follows:

                 d = OB - OA

                 d = < 13 , -15 > - < 3 , -5 >  

                 d = < 10 , -10 >

The fixed point on the line is taken. We will take point A. The vector equation of line from point A to point B is expressed as:

                < x , y > = OA + s*d

                < x , y > = < 3, -5 > + s* < 10 , -10 >  

The above equation satisfies all the points that lies on the line AB. To determine the coordinates of ( C ). We will plug in the appropriate value of parameter ( s ) and evaluate.

So point C is 4/5 th the magnitude of the distance AB from A. Hence, s = 4/5 as follows:

               < x , y > = < 3 , -5 > + ( 4/5 ) * < 10 , -10 >  

               < x , y > = < 3 , -5 > + < 8 , -8 >  

              < x , y > = < 11 , -11 >   ... Answer

8 0
3 years ago
What is the slope of the line that passed through (3,-4) and (4,9)
Advocard [28]

Step-by-step explanation:

<u>Step 1:  Find the slope</u>

<u />m=\frac{y_2-y_1}{x_2-x_1}

m=\frac{9-(-4)}{4-3}

m =\frac{9+4}{1}

m=13

Answer: The slope is 13

5 0
3 years ago
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