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dexar [7]
2 years ago
8

Class A has 13 pupils and class B has 16 pupils.

Mathematics
1 answer:
andre [41]2 years ago
7 0

Answer:

ok so we can just add 20 + 45 then divide by 2

20+45=65/2=32.5

32.5

Hope This Helps!!!

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Which triangle congruence is this?<br> SSS<br> SAS<br> ASA<br> AAS<br> HL
MrRissso [65]

Answer:

HL

Step-by-step explanation:

The Hypotenuse-Leg Theorem states that two right triangles are congruent if and only if the hypotenuse and a leg of one right triangle are congruent to the hypotenuse and a leg of the other right triangle.

7 0
3 years ago
Find the value of x. 6+3x and x+14?
LenaWriter [7]
Simplifying
x + 6 = 3x + -14

Reorder the terms:
6 + x = 3x + -14

Reorder the terms:
6 + x = -14 + 3x

Solving
6 + x = -14 + 3x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3x' to each side of the equation.
6 + x + -3x = -14 + 3x + -3x

Combine like terms: x + -3x = -2x
6 + -2x = -14 + 3x + -3x

Combine like terms: 3x + -3x = 0
6 + -2x = -14 + 0
6 + -2x = -14

Add '-6' to each side of the equation.
6 + -6 + -2x = -14 + -6

Combine like terms: 6 + -6 = 0
0 + -2x = -14 + -6
-2x = -14 + -6

Combine like terms: -14 + -6 = -20
-2x = -20

Divide each side by '-2'.
x = 10

Simplifying
x = 10
6 0
3 years ago
Read 2 more answers
A boat is pulled into a dock by a rope attached to the bow of the boat and passing through a pulley on the dock that is 1 m high
Agata [3.3K]

Answer:

dy/dt = 1.02 m/s

Step-by-step explanation:

First of all, let the distance of the dock above the bow of the boat be represented by x.

Also, let the distance of the boat from the dock be represented by y.

Let z represent the length of the rope.

Now, we can use pythagoras theorem to find a relationship between x, y and z since they form a right angle triangle where the vertical part is the dock, the base represents the water and the hypotenuse represents the rope.

Thus;

x² + y² = z²

Using implicit differentiation, we have;

2x(dx/dt) + 2y(dy/dt) = 2z(dz/dt)

We are given that the dock is 1 meter above the bow. Thus, x = 1

Also, the height is not changing and so dx/dt = 0

We are told the dock is 5 feet away from the boat. Thus, y = 5

dy/dt is is the speed we are looking for which is the rate at which the boat is approaching the dock.

We are not given the value of z but we can find it by using pythagoras theorem since we know the dock is 1 meter above the bow and the boat is 5 m away.

Thus;

z = √(1² + 5²)

z = √26

We are told the rope is being pulled in at the rate of 1 m/s. Thus; dz/dt = 1

Plugging all relevant values into the differentiation equation above gives;

2(1)(0) + 2(5)(dy/dt) = 2(√26)(1)

10(dy/dt) = 2√26

Divide both sides by 10 to get:

dy/dt = (√26)/5

dy/dt = 1.02 m/s

5 0
3 years ago
the image from reflecting a figure in the fourth quadrant over the y-axis. in what quadrant is the image is​
Alekssandra [29.7K]
It should be in the third quadrant
5 0
3 years ago
I would like to know the right answer of this graph.
jeka94

Answer:

(6,-4)

Step-by-step explanation:

P(-2,2)

-2 - 4 = 6

2 - 6 = -4

4 0
3 years ago
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