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Salsk061 [2.6K]

3 years ago

5

A 155 pound man burns about 500 calories per hour playing raquetball. one pound is equal to 3500 calories. how long will it take

to burn 1 pound

1 answer:

horrorfan [7]3 years ago

3 0

7 hours to burn 3500 calories

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Someone please help me with these 2 questions I will mark brainlist!!!!

Tamiku [17]

ANSWER for the first one:
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A= 40.5 cm2

ANSWER for the second one:
9*3= 27
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3 years ago

Is the relation a function?

mario62 [17]

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Naya [18.7K]

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What is the equation x^2+12x-3=16 written in the form (x-p)^2=q using the method of completing the square ?

Alexus [3.1K]

Step-by-step explanation:

${x}^{2} + 12x - 3 = 16$

${x}^{2} + 12x = 19$

${x}^{2} + 12x + 36 = 19 + 36$

$(x + 6) {}^{2} = 55$

3 0

3 years ago

Describe and correct the error in finding csc θ, given that θ is an acute angle of a right triangle and cos θ =7/11

a_sh-v [17]

Answer:

<h2>cosecθ = 1/sinθ = 11/6√2</h2>

Step-by-step explanation:

Given that cos θ =7/11, cosec θ = 1/sinθ in trigonometry.

Based on SOH, CAH, TOA;

cosθ = adjacent/hypotenuse = 7/11

adjacent = 7 and hyp = 11

Since sinθ = opp/hyp, we need to get the opposite to be able to calculate sinθ.

Using pythagoras theorem to get the opposite;

$hyp^{2} = adj^{2} + opp ^{2} \\opp = \sqrt{hyp^{2} - adj^{2} } \\opp = \sqrt{11^{2} - 7^{2}} \\opp = \sqrt{72} \\opp = 6\sqrt{2}$

sinθ = 6√2/11

cosecθ = 1/sinθ = 1/( 6√2/11)

cosecθ = 1/sinθ = 11/6√2

Note the error; cscθ $\neq$ 1/cosθ but cscθ = 1/sinθ

6 0

3 years ago