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Salsk061 [2.6K]
3 years ago
5

A 155 pound man burns about 500 calories per hour playing raquetball. one pound is equal to 3500 calories. how long will it take

to burn 1 pound
Mathematics
1 answer:
horrorfan [7]3 years ago
3 0
7 hours to burn 3500 calories 
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Someone please help me with these 2 questions I will mark brainlist!!!!
Tamiku [17]
ANSWER for the first one:
A=a+b/2*h
A= 4.5+9/2*6
A= 40.5 cm2

ANSWER for the second one:
9*3= 27
3*3= 9
9*3= 27
A= 63 cm2
8 0
3 years ago
Is the relation a function?
mario62 [17]

Yes it is because none of the x are the same number making it a function.

6 0
3 years ago
This is due tomorrow and I k ow for a fact these are both wrong, someone help
Naya [18.7K]
#1 answer is D and #2 answer is D also
6 0
3 years ago
Read 2 more answers
What is the equation x^2+12x-3=16 written in the form (x-p)^2=q using the method of completing the square ?
Alexus [3.1K]

Step-by-step explanation:

{x}^{2}  + 12x -  3 = 16

{x}^{2}  + 12x = 19

{x}^{2}  + 12x + 36 = 19 + 36

(x + 6) {}^{2}  = 55

3 0
3 years ago
Describe and correct the error in finding csc θ, given that θ is an acute angle of a right triangle and cos θ =7/11
a_sh-v [17]

Answer:

<h2>cosecθ = 1/sinθ = 11/6√2</h2>

Step-by-step explanation:

Given that  cos θ =7/11, cosec θ = 1/sinθ in trigonometry.

Based on SOH, CAH, TOA;

cosθ = adjacent/hypotenuse = 7/11

adjacent = 7 and hyp = 11

Since sinθ = opp/hyp, we need to get the opposite to be able to calculate sinθ.

Using pythagoras theorem to get the opposite;

hyp^{2} = adj^{2}  + opp ^{2}  \\opp = \sqrt{hyp^{2} - adj^{2}  } \\opp = \sqrt{11^{2} - 7^{2}} \\opp = \sqrt{72} \\opp = 6\sqrt{2}

sinθ = 6√2/11

cosecθ = 1/sinθ = 1/( 6√2/11)

cosecθ = 1/sinθ = 11/6√2

Note the error; cscθ\neq 1/cosθ but cscθ = 1/sinθ

6 0
3 years ago
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