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Anon25 [30]
2 years ago
7

Help plssssss1. (x +3) 22. 6÷2(1+2)3. 15-1(12÷4+1)​

Mathematics
1 answer:
Lisa [10]2 years ago
5 0
1. 2x+7
2. 9
3.11
I help u there aowonxpwkdowiwvbwicbwocbiwcb
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PLEASE HELP I NEED HELP BADDD PLS CORRECT ANSWERS ONLY
abruzzese [7]

Answer:

Hi,

Step-by-step explanation:

Answer B : 51

1+4+7+10+13+16=51

6 0
2 years ago
PLS HELP ASAP!!! I WILL GIVE BRAINLIEST!!
denis-greek [22]

Answer:

The fish is closer to the surface of the water because |+4| = 4 and |−3| = 3, and 3 < 4.

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Pls help me not fail
nignag [31]

Answer:

D

Step-by-step explanation:

Using the Cosine rule to find AC

AC² = BC² + AB² - (2 × BC × AB × cosB )

      = 18² + 12² - ( 2 × 18 × 12 × cos75° )

      = 324 + 144 - 432cos75°

      = 468 - 111.8

      = 356.2 ( take the square root of both sides )

AC = \sqrt{356.2} ≈ 18.9

-----------------------------------------

Using the Sine rule to find ∠ A

\frac{18}{sinA} = \frac{18.9}{sin75} ( cross- multiply )

18.9 sinA = 18 sin75° ( divide both sides by 18.9 )

sinA = \frac{18sin75}{18.9} , then

∠ A = sin^{-1} ( \frac{18sin75}{18.9} ) ≈ 66.9°

4 0
3 years ago
At which points are the tangents drawn to the ellipse x 2 + y 2 = [ a ] x + [ a ] y parallel to
In-s [12.5K]

The given equation of the ellipse is x^2 + y^2 = 2 x + 2 y

At tangent line, the point is horizontal with the x-axis therefore slope = dy / dx = 0

<span>So we have to take the 1st derivative of the equation then equate dy / dx to zero.</span>

x^2 + y^2 = 2 x + 2 y

x^2 – 2 x = 2 y – y^2

(2x – 2) dx = (2 – 2y) dy

(2x – 2) / (2 – 2y) = 0

2x – 2 = 0

x = 1

 

To find for y, we go back to the original equation then substitute the value of x.

x^2 + y^2 = 2 x + 2 y

1^2 + y^2 = 2 * 1 + 2 y

y^2 – 2y + 1 – 2 = 0

y^2 – 2y – 1 = 0

Finding the roots using the quadratic formula:

y = [-(- 2) ± sqrt ( (-2)^2 – 4*1*-1)] / 2*1

y = 1 ± 2.828

y = -1.828 , 3.828

 

<span>Therefore the tangents are parallel to the x-axis at points (1, -1.828) and (1, 3.828).</span>

3 0
3 years ago
Which equation represents a circle with the same radius as
sattari [20]

Answer :

(x+1)^2+(y-1)^2=4^2 and (x+1)^2+(y-1)^2=16

Step-by-step explanation:

Given : A circle with the same radius as  the circle shown but with a center at (-1.1).

To find : Which equation represents a circle ?

Solution :

The equation of a circle with center (h,k) and radius r is given by :

(x-h)^2+(y-k)^2=r^2

Here, we are given (h,k)=(-1,1)

and radius r=4 units

So, equation of circle will be :

(x-(-1))^2+(y-1)^2=4^2

(x+1)^2+(y-1)^2=4^2

or (x+1)^2+(y-1)^2=16

Therefore, the required equations of circle are

(x+1)^2+(y-1)^2=4^2 and (x+1)^2+(y-1)^2=16

7 0
3 years ago
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