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Anon25 [30]
2 years ago
7

Help plssssss1. (x +3) 22. 6÷2(1+2)3. 15-1(12÷4+1)​

Mathematics
1 answer:
Lisa [10]2 years ago
5 0
1. 2x+7
2. 9
3.11
I help u there aowonxpwkdowiwvbwicbwocbiwcb
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Write down the next term in each of the following sequences
Archy [21]
Answer is:
a) 32
b) 59
Both are arithmetic sequences
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3 years ago
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70% of the 40 members of the club voted. how many voted ?
REY [17]

Answer:

28 members up in that club have voted.

6 0
3 years ago
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Choose the option with the proper number of sig figs
marishachu [46]
\text{ 2 }\times10^8

Explanation:\begin{gathered} \text{Given:} \\ \frac{9\text{ }\times10^9}{4.5\text{ }\times10^1} \end{gathered}

let's break down the expression to get the final result:

\begin{gathered} \frac{9\text{ }\times10^9}{4.5\text{ }\times10^1}\text{ = }\frac{9}{4.5}\times\text{ }\frac{10^9}{10^1} \\ \frac{9}{4.5}\text{ = }\frac{9\text{ }\times\text{ 10}}{4.5\text{ }\times\text{ 10}}\text{ = }\frac{90}{45} \\ \frac{9}{4.5}\text{ = }2 \\  \\ \frac{10^9}{10^1}\colon\text{ when we divide exponents with same base, } \\ we\text{ take one of the base and combine the exponents by subtracting them:} \\ \frac{10^9}{10^1}=10^{9-1} \\ \frac{10^9}{10^1}=10^8 \end{gathered}\begin{gathered} \frac{9}{4.5}\times\text{ }\frac{10^9}{10^1}\text{ = 2 }\times10^8 \\  \\ \text{when dividing decimals, }the\text{ least number of }significant\text{ }figures\text{ in the problem}, \\ \text{ }\det ermines\text{ the significant figures in the answer} \\ 9\text{ = 1 significant, 4.5 = 2 significant} \\ \text{The least significant is 1} \\  \\ \frac{9\text{ }\times10^9}{4.5\text{ }\times10^1}\text{ = 2 }\times10^8 \end{gathered}

6 0
1 year ago
Vance wants to determine if an old photo frame is still rectangular. The height of the frame is
sveticcg [70]

Answer:

<em>The old photo frame is still rectangular</em>

Step-by-step explanation:

<u>Rectangles</u>

The rectangle shape can be identified because it has 4 internal angles of 90° each. The diagonal forms with two adjacent sides a right triangle where the Pythagora's Theorem must stand. Being a and b the length of the sides of the rectangle and d the diagonal, then:

d^2=a^2+b^2

Vince's photo frame has dimensions of 8 inches and 6 inches, with a diagonal of 10 inches. If the above condition is met, then the frame is still rectangular.

Calculating:

10^2=6^2+8^2

100=36+64

100=100

Since the condition is met, the old photo frame is still rectangular

4 0
3 years ago
Can somebody help me out
Y_Kistochka [10]

Answer:

dufenschmertz evil incorporated...

Step-by-step explanation:

after hours ;)

6 0
2 years ago
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