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Murljashka [212]
3 years ago
6

Need help with homework independent practice lesson 5 negative exponents

Mathematics
1 answer:
adell [148]3 years ago
3 0
What's the problem you need help with
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Need help with a math question
LiRa [457]

Answer:

x=7

Step-by-step explanation:

Equate the angles 7x-7 and 4x+14 and solve:

7x-7 = 4x+14

7x-4x = 14+7

3x = 21

x = 7

5 0
3 years ago
Read 2 more answers
Please answer this correctly
irinina [24]

26 = orchestra

11 + 13 = 24 = choir

26 x 2 = 52 = band

52 + 24 + 26 = 102 people in all the following on top.

Hope this helped!

Nate

4 0
3 years ago
Which expression is equivalent to x^4 - 12x^2 + 36
lord [1]
X⁴ - 12x² + 36

This is the equivalent expression.
(x²-6)²

1) (x²-6)*(x²-6)
2) x²(x²) + x²(-6) -6(x²) -6(-6)  (distributive multiplication)
3) x⁴ - 6x² - 6x² + 36 = x⁴ - 12x² + 36  (group together figures that are the same value)



7 0
3 years ago
Read 2 more answers
CAN SOMEONE HELP. i will give 150 points if some one can explain and solve you have to find the missing angle measures.
Tems11 [23]

Answer:

\angle ACB=40^{\circ}, \angle ABC=63^{\circ}

Step-by-step explanation:

Finding x:

We know that \angle DAB=180^{\circ}, because it's a straight line. So, \angle CAB=180^{\circ}-103^{\circ}=77^{\circ}.

We know that the sum of the angles of any triangle will be 180^{\circ}.

So, we have that (3x-14)+(3x+9)+77=180.

Combining like terms on the left gives 6x+72=180.

Subtracting 72 from both sides gives 6x=108.

Dividing both sides by 6 gives x=18.

Finding missing angle measures:

\angle ACB=3x-14=3(18)-14=54-14=40.

\angle ABC=3x+9=3(18)+9=54+9=63.

So, \angle ACB=40^{\circ} and \angle ABC=63^{\circ} and we're done!

Note: \angle ACB+\angle ABC=\angle CAD. Coincidence? If not, try and prove it!

7 0
3 years ago
The sum of 1/5 and 3/4
ICE Princess25 [194]
Change the 1/5 to 4/20 and the 3/4 to 15/20 and then add them together
4 0
3 years ago
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