1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
damaskus [11]
3 years ago
7

World wind energy generating1 capacity, W , was 371 gigawatts by the end of 2014 and has been increasing at a continuous rate of

approximately 16.8% per year. Assume this rate continues. (Generating capacity is the maximum amount of power generated per unit time.) (a) Give a formula for W , in gigawatts, as a function of time, t , in years since the end of 2014 . W= gigawatts (b) When is wind capacity predicted to pass 600 gigawatts? Wind capacity will pass 600 gigawatts during the year?
Mathematics
1 answer:
Sunny_sXe [5.5K]3 years ago
7 0

Answer:

a) W(t) = 371(1.168)^{t}

b) Wind capacity will pass 600 gigawatts during the year 2018

Step-by-step explanation:

The world wind energy generating capacity can be modeled by the following function

W(t) = W(0)(1+r)^{t}

In which W(t) is the wind energy generating capacity in t years after 2014, W(0) is the capacity in 2014 and r is the growth rate, as a decimal.

371 gigawatts by the end of 2014 and has been increasing at a continuous rate of approximately 16.8%.

This means that

W(0) = 371, r = 0.168

(a) Give a formula for W , in gigawatts, as a function of time, t , in years since the end of 2014 . W= gigawatts

W(t) = W(0)(1+r)^{t}

W(t) = 371(1+0.168)^{t}

W(t) = 371(1.168)^{t}

(b) When is wind capacity predicted to pass 600 gigawatts? Wind capacity will pass 600 gigawatts during the year?

This is t years after the end of 2014, in which t found when W(t) = 600. So

W(t) = 371(1.168)^{t}

600 = 371(1.168)^{t}

(1.168)^{t} = \frac{600}{371}

(1.168)^{t} = 1.61725

We have that:

\log{a^{t}} = t\log{a}

So we apply log to both sides of the equality

\log{(1.168)^{t}} = \log{1.61725}

t\log{1.168} = 0.2088

0.0674t = 0.2088

t = \frac{0.2088}{0.0674}

t = 3.1

It will happen 3.1 years after the end of 2014, so during the year of 2018.

You might be interested in
What is the most likely meaning of the word endangered?
schepotkina [342]

Answer:

exposed is another word for endangered

8 0
3 years ago
Read 2 more answers
40 students at a particular school are randomly selected for a survey. 18 have blue eyes. If there are 400 students at this scho
podryga [215]
A reasonable estimate would be 180 students with blue eyes
7 0
3 years ago
Read 2 more answers
6 Narong’s family bought 3 shirts, 2 pairs of jeans,
Bas_tet [7]
The answer is $204.Hope this helps.
5 0
4 years ago
Troy’s canoe is 18 feet long. Ariel’s canoe is the length of Troy’s canoe.
tankabanditka [31]
Well the answer i think is going to be 18

3 0
4 years ago
Read 2 more answers
How can you show your work on rounding
MAXImum [283]
U can show your work by underlining what your rounding and showing which place it is it the right of it but there is no mathematical work
6 0
4 years ago
Read 2 more answers
Other questions:
  • -4x+14+20x=2(10x-3)<br> not sure how to tackle this
    6·1 answer
  • Find the derivative of the function f(x)= (x^2-x) ^2
    5·2 answers
  • What is the percent of increase from 5050 to 6767 ?
    12·1 answer
  • The equation of a line is given by y=m+b. Solve for M
    10·1 answer
  • Netiquette is defined as the acceptable way of communicating with others on the Internet. true or False
    8·1 answer
  • For questions 9 and 11, solve for the remaining angles.
    14·1 answer
  • the distance from a driveway to the closest house is 12,672 feet. How far is that in miles. (1 mile=5280 feet)
    12·2 answers
  • True False x-sqrt6 is a factor of x^4-36
    8·1 answer
  • Water and oil are mixed in the ratio 3:5. Find the density of the mixture if the density of water is 1g/cm ^3 and that of oil is
    12·1 answer
  • Drag each statement to show whether it is true, based on the graph.
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!