Answer:
a) 
b) Wind capacity will pass 600 gigawatts during the year 2018
Step-by-step explanation:
The world wind energy generating capacity can be modeled by the following function

In which W(t) is the wind energy generating capacity in t years after 2014, W(0) is the capacity in 2014 and r is the growth rate, as a decimal.
371 gigawatts by the end of 2014 and has been increasing at a continuous rate of approximately 16.8%.
This means that

(a) Give a formula for W , in gigawatts, as a function of time, t , in years since the end of 2014 . W= gigawatts



(b) When is wind capacity predicted to pass 600 gigawatts? Wind capacity will pass 600 gigawatts during the year?
This is t years after the end of 2014, in which t found when W(t) = 600. So




We have that:

So we apply log to both sides of the equality





It will happen 3.1 years after the end of 2014, so during the year of 2018.