Answer:
The width of the rectangle is 56 and the length is 48
Step-by-step explanation:
divide the perimeter in half (52 + 52)
then subtract 4 from one of the 52's
you get the answer of 56 and 48
Your answer can be checked by conferming that 56 - 48 = 8 so the width of a rectangle is 8 inches longer than its length.
We'll represent Louise's, Tammy's, Delores's, and Sheryl's point values with 
, 
, 
, and 
respectively since each one is 1 point more than the last.
Add all of these values up and set it all equal to 
.
Now, simplify.
Subtract 
on both sides.
Divide both sides by 
.
Since Louise's score is , the answer is 
.
<h3>Double-checking</h3>
To verify our answer, add the point totals , 
, 
, and 
.
This equals , so we can be sure the answer is correct.
1. Measure and angle in degree
The answer is choice D
-----------------------------------------
Explanation:
We can rule out choice B and choice C which are y = 2.4^x and y = 3.5^x respectively. Why can we eliminate these? Because they are growth functions (the bases are larger than 1). The graph shown is a decay function. It goes downhill as you read it from left to right.
The answer is either choice A or choice D
If we plug in x = -2 into the equations for A and D, we get
y = 0.65^x = 0.65^(-2) = 2.36686
y = 0.32^x = 0.32^(-2) = 9.765625
The result for choice D is much closer to what the graph is showing. The graph appears to have the point (-2,11) on the curve. So that's why choice D is the best answer.
Note: the graph is a bit small and its not entirely clear which points are on this graph other than (0,1). So this is a bit of educated guesswork.
Answer:
The difference of 8 times a number r and 12 is solved for a number r and is given by 
Step-by-step explanation:
Given problem is the difference of 8 times a number r and 12
It can be written as
To simplify the above expression :
8r-12
( using addition property of equality )
(using division property of equality )
Therefore
Therefore the difference of 8 times a number r and 12 is solved for a number r and is given by
