All categories

3 years ago

1: In order to solve the inequality -1/4 x > 8, which of the following steps must be done?

Mathematics

1 answer:

pogonyaev3 years ago

3 0

Answer:

Step-by-step explanation:

-1/4x>8

x>8/(-1/4)

x>(8/1)(-4/1)

x>-32/1

x>-32

x<-32

The answer is D.

--------------------------

-3t+7>=9

-3t>=9-7

-3t>=2

t>=2/-3

t>=-2/3

t<=-2/3

The answer is A.

You might be interested in

HELP ME! FAST! Please help me! ASAP! PLEASE! SOMEONE HELP ME!

Harrizon [31]

I hope this helps you

5 0

3 years ago

A right triangle has a length of 30 and a side with a length of 18. A side with a length of 24 is opposite angle theta. What sta

tekilochka [14]

Answer:

$\text{A. }\cos \theta = \frac{3}{5}$

Step-by-step explanation:

See attached file for complete work.

Download pdf

7 0

2 years ago

What is the equation of the parabola?

Neporo4naja [7]

Answer:

y = -1/8 x² + 5

Step-by-step explanation:

Parabola opens vertically and vertex (h,k) = (0,5), pass point (4,3)

basic formula: y = a(x - h)² + k

y = a (x-0)² + 5

y = ax² + 5 pass (4,3)

3 = 16a + 5

a = (3-5)/16 = -1/8

equation: y = -1/8 x² + 5

check: pass another point (-4,3)

-1/8 * (-4)² + 5 = -2 + 5 = 3

5 0

3 years ago

sally's $1800 savings is in two accounts.Her total interest for the year was $93 from one account earning 6% interest and anothe

myrzilka [38]

Answer:

$500 invested at 3%

$1300 invested at 6%

Step-by-step explanation:

8 0

3 years ago

4/x-1+6/x+1=-12/x^2-1

Mademuasel [1]

$\frac{4}{x - 1} + \frac{6}{x + 1} = \frac{-12}{x^{2} - 1}$

$\frac{4(x + 1)}{(x - 1)(x + 1)} + \frac{6(x - 1)}{(x - 1)(x + 1)} = \frac{-12}{x^{2} - 1}$

$\frac{4x + 4}{x^{2} - 1} + \frac{6x - 6}{x^{2} - 1} = \frac{-12}{x^{2} - 1}$

$\frac{10x - 2}{x^{2} - 1} = \frac{-12}{x^{2} - 1}$

$(10x - 2)(x^{2} - 1) = -12(x^{2} - 1)$
$10x^{3} - 10x^{2} - 2x^{2} + 2 = -12(x^{2}) + 12(1)$
$10x^{3} - 12x^{2} + 2 = -12x^{2} + 12$
$10x^{3} - 12x^{2} + 12x^{2} + 2 = -12x^{2} + 12x^{2} + 12$
$10x^{3} + 2 - 2 = 12 - 2$
$\frac{10x^{3}}{10} = \frac{10}{10}$

$x^{3} = 1$
$x = 1$

4 0

3 years ago