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Maksim231197 [3]
3 years ago
11

What is a correct first step in solving the inequality –4(3 – 5x)≥ –6x + 9?

Mathematics
2 answers:
Bumek [7]3 years ago
7 0
The first thing you would need to know is PEMDAS. Also stands for parenthesis, exponents, multiplication, division, addition and subtraction. 
This shows the order you should follow when solving problems like these. 

This problem states that the first thing that you would look for is parenthesis. There are parenthesis in this statement, but there's a number before the parenthesis. In this case, your first step would be to take -4(3) - -4(-5x) 
The first step is using distributive property to -4(3-5x) to get
-4(3) - (-4)-5x 


xenn [34]3 years ago
7 0

Answer:

The Correct answer is

12+20x ≥-6x+9

Step-by-step explanation:

You have to distribute

HOPE THIS HELPS:)

STAY SAFE

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Simplify.<br><br> 9y+11z+7y−4z<br><br> What is the answer?
tigry1 [53]
The answer is
16y + 7z
6 0
4 years ago
An adult elephant drinks about 225 liters of water each day. Is the
MissTica

Answer:

Yes, the number of days are proportional to the number of liters of water the elephant drinks.

Step-by-step explanation:

1 day: 225L  2 days: 450L  3 days: 675L  4 days: 900L

There is a proportional pattern to it.

8 0
4 years ago
A grocery store sells a bag of 5 lemons for $2. What is the unit cost of each lemon in the bag? [ONLY PUT THE NUMBER ANSWER] *
Anna [14]

Answer:

0.4

Step-by-step explanation:

2/5 =0.4

The unit cost =0.4

6 0
3 years ago
Find the value of b that will make the equation sin 62°= cos B true when 0°
KiRa [710]

Hello from MrBillDoesMath!

Answer:

b = 28 degrees

Discussion:

In general,

sin (90 - @) = cos(@)

Set 90 [email protected] = 62  => @ = 28 so

sin (90-28) = sin(62) = cos(28)    => b = 28

Thank you,

MrB

4 0
3 years ago
Use the following image to assist in your answer.<br> a =<br> - 6<br> - 9<br> - 4
vfiekz [6]

Step-by-step explanation:

Pythagoras' theorem for the smallest one :

c^2 = 4^2 + 6^2

c^2 = 16 + 36

c^{2} = 52

Pythagoras' theorem for the middle one :

b^{2} = 6^{2} + a^{2}

Pythagoras' theorem for the biggest one :

(4+a)^2 = c^2 + b^2

16 + 8a + a^2 = 52 + b^2

Using the formula before (for b^2) it becomes :

16 + 8a + a^2 = 52 + (6^2 + a^2)

16 + 8a + a^2 = 52 + 6^2 + a^2

16 + 8a = 52 + 6^2

16 + 8a = 52 + 36

16+8a = 88

8a = 88-16

8a = 72

a = \frac{72}{8}

a = 9

Verifying :

b^2 = 6^2 + a^2

b^2 = 36 + 81

b^2 = 117

b^{2} = 117

The biggest one :

(4+a)^2 = c^2 + b^2

(4+9)^2 = 52 + 117

13^2 = 169

True

8 0
3 years ago
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